OpenEuphoria

Re: what am i doing wrong here.

• Posted by "Hayden McKay" <hmck1 at dodo.com.au> Dec 16, 2003
• 474 views

I found another way to get the any root of a number to 100% accuracy.
(below)

-- atom = root(atom digit, integer factor)
-- Calculate the root of a digit.
-- Returns the desired root.
global function root(atom a,integer n)
  a = power(a,(1/n))
  return a
end function




----- Original Message ----- 
From: "Pete Lomax" <petelomax at blueyonder.co.uk>
To: <EUforum at topica.com>
Sent: Tuesday, December 16, 2003 10:46 PM
Subject: Re: what am i doing wrong here.


>
>
> On Tue, 16 Dec 2003 17:05:38 +1100, Hayden McKay <hmck1 at dodo.com.au>
> wrote:
>
> >x = 86.0001776 - d -- x = 0.0001776
> >x = i - d -------------- x = 1.776461434e-005 -- why?
>
> Those two numbers are the same, just printed differently.
>
> Try using printf(1,"%1.7f\n",{x}) instead.
>
> >I'm trying to do this so I can get the root of x
> >and subtract it from c so that
> >c powerd again will equal ~exactly 86.
>
> This might be what you're after:
>
> function root(atom r, integer x)
> return power(2.718281828,log(r)/x)
> end function
>
> Any non-rational numbers will always be ~e-14 off.
>
>
>
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