what am i doing wrong here.
- Posted by "Hayden McKay" <hmck1 at dodo.com.au> Dec 16, 2003
- 476 views
--=======AVGMAIL-3FDEA0B2627F======= ------=_NextPart_000_001C_01C3C3F6.D3FC3C00 The first example works, the second one does'nt x = 86.0001776 - d -- x = 0.0001776 Ex 1: atom c,i,d,x d = 86 c = root(d,3) -- c = 4.414005266 -- (My function) i = power(c,3) -- i = 86.0001776 x = 86.0001776 - 86 -- x = 0.0001776 print(1,x) Ex 2: atom c,i,d,x d = 86 c = root(d,3) -- c = 4.414005266 i = power(c,3) -- i = 86.0001776 x = i - d -------------- x = 1.776461434e-005 -- why? print(1,x) I'm trying to do this so I can get the root of x and subtract it from c so that c powerd again will equal ~exactly 86. Is this a binary bit error thats grown? This is all my root routine needs to do to accomadate for all root factors since i = root(86,9) -- i = around 1.478xxxxx x = power(i,9) -- x = arround 33.69xxxxx (i needs to have +0.163) so that when powered it equals 86. --- Outgoing mail is certified Virus Free. Checked by AVG anti-virus system (http://www.grisoft.com). Version: 6.0.551 / Virus Database: 343 - Release Date: 11/12/03 ------=_NextPart_000_001C_01C3C3F6.D3FC3C00 Content-Type: text/html; charset=iso-8859-1 Content-Transfer-Encoding: 8bit <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN"> <HTML><HEAD> <META http-equiv=Content-Type content="text/html; charset=iso-8859-1"> <META content="MSHTML 6.00.2800.1276" name=GENERATOR> <STYLE></STYLE> </HEAD> <BODY bgColor=#ffffff> <DIV><FONT face=Arial size=2>The first example works, the second one does'nt</FONT></DIV> <DIV><FONT face=Arial size=2>x = 86.0001776 - d -- x = 0.0001776</FONT></DIV> <DIV><FONT face=Arial size=2>Ex 1:</FONT></DIV> <DIV> <FONT face=Arial size=2>atom c,i,d,x<BR>d = 86<BR>c = root(d,3) -- c = 4.414005266 -- (My function)<BR>i = power(c,3) -- i = 86.0001776<BR>x = 86.0001776 - 86 -- x = 0.0001776<BR>print(1,x)<BR></FONT></DIV> <DIV><FONT face=Arial size=2></FONT> </DIV> <DIV><FONT face=Arial size=2>Ex 2:</FONT></DIV> <DIV> <FONT face=Arial size=2>atom c,i,d,x<BR>d = 86<BR>c = root(d,3) -- c = 4.414005266<BR>i = power(c,3) -- i = 86.0001776<BR>x = i - d -------------- x = 1.776461434e-005 -- why?<BR>print(1,x)<BR></FONT></DIV> <DIV><FONT face=Arial size=2>I'm trying to do this so I can get the root of x </FONT></DIV> <DIV><FONT face=Arial size=2>and subtract it from c so that </FONT></DIV> <DIV><FONT face=Arial size=2>c powerd again will equal ~exactly 86.</FONT></DIV> <DIV><FONT face=Arial size=2></FONT> </DIV> <DIV><FONT face=Arial size=2>Is this a binary bit error thats grown?</FONT></DIV> <DIV><FONT face=Arial size=2></FONT> </DIV> <DIV><FONT face=Arial size=2>This is all my root routine needs to do to accomadate for all</FONT></DIV> <DIV><FONT face=Arial size=2>root factors since </FONT></DIV> <DIV><FONT face=Arial size=2>i = root(86,9) -- i = around 1.478xxxxx</FONT></DIV> <DIV><FONT face=Arial size=2>x = power(i,9) -- <DIV><FONT face=Arial size=2>x = arround 33.69xxxxx (i needs to have +0.163)</FONT></FONT></DIV></DIV> <DIV><FONT face=Arial size=2>so that when powered it equals 86.</FONT></DIV> <DIV> </DIV> <DIV><FONT face=Arial size=2><BR>---<BR>Outgoing mail is certified Virus Free.<BR>Checked by AVG anti-virus system (<A href="http://www.grisoft.com">http://www.grisoft.com</A>).<BR>Version: 6.0.551 / ------=_NextPart_000_001C_01C3C3F6.D3FC3C00-- --=======AVGMAIL-3FDEA0B2627F======= Content-Type: text/plain; x-avg=cert; charset=iso-8859-2 Content-Transfer-Encoding: 8bit Content-Disposition: inline Content-Description: "AVG certification" Outgoing mail is certified Virus Free. Checked by AVG anti-virus system (http://www.grisoft.com). Version: 6.0.551 / Virus Database: 343 - Release Date: 11/12/03 --=======AVGMAIL-3FDEA0B2627F=======--