1. what am i doing wrong here.

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The first example works, the second one does'nt
x = 86.0001776 - d -- x = 0.0001776
Ex 1:
 atom c,i,d,x
d = 86
c = root(d,3) -- c = 4.414005266 -- (My function)
i = power(c,3) -- i = 86.0001776
x = 86.0001776 - 86 -- x = 0.0001776
print(1,x)


Ex 2:
 atom c,i,d,x
d = 86
c = root(d,3) -- c = 4.414005266
i = power(c,3) -- i = 86.0001776
x = i - d -------------- x = 1.776461434e-005 -- why?
print(1,x)

I'm trying to do this so I can get the root of x 
and subtract it from c so that 
c powerd again will equal ~exactly 86.

Is this a binary bit error thats grown?

This is all my root routine needs to do to accomadate for all
root factors since 
i = root(86,9) -- i = around 1.478xxxxx
x = power(i,9) -- 
x = arround 33.69xxxxx (i needs to have +0.163)
so that when powered it equals 86.


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<DIV><FONT face=Arial size=2>The first example works, the second one 
does'nt</FONT></DIV>
<DIV><FONT face=Arial size=2>x&nbsp;= 86.0001776 - d -- x = 
0.0001776</FONT></DIV>
<DIV><FONT face=Arial size=2>Ex 1:</FONT></DIV>
<DIV>&nbsp;<FONT face=Arial size=2>atom c,i,d,x<BR>d = 86<BR>c&nbsp;= root(d,3) 
-- c = 4.414005266 -- (My function)<BR>i = power(c,3) -- i = 86.0001776<BR>x 
=&nbsp;86.0001776 - 86 -- x = 0.0001776<BR>print(1,x)<BR></FONT></DIV>
<DIV><FONT face=Arial size=2></FONT>&nbsp;</DIV>
<DIV><FONT face=Arial size=2>Ex 2:</FONT></DIV>
<DIV>&nbsp;<FONT face=Arial size=2>atom c,i,d,x<BR>d = 86<BR>c&nbsp;= root(d,3) 
-- c = 4.414005266<BR>i = power(c,3) -- i = 86.0001776<BR>x = i - d 
-------------- x = 1.776461434e-005 -- why?<BR>print(1,x)<BR></FONT></DIV>
<DIV><FONT face=Arial size=2>I'm trying to do this so I can get the root of x 
</FONT></DIV>
<DIV><FONT face=Arial size=2>and subtract it from c so that </FONT></DIV>
<DIV><FONT face=Arial size=2>c&nbsp;powerd again will equal ~exactly 
86.</FONT></DIV>
<DIV><FONT face=Arial size=2></FONT>&nbsp;</DIV>
<DIV><FONT face=Arial size=2>Is this a binary bit error thats 
grown?</FONT></DIV>
<DIV><FONT face=Arial size=2></FONT>&nbsp;</DIV>
<DIV><FONT face=Arial size=2>This is all my root routine needs to do to 
accomadate for all</FONT></DIV>
<DIV><FONT face=Arial size=2>root factors since </FONT></DIV>
<DIV><FONT face=Arial size=2>i = root(86,9) --&nbsp;i&nbsp;= around 
1.478xxxxx</FONT></DIV>
<DIV><FONT face=Arial size=2>x = power(i,9) -- 
<DIV><FONT face=Arial size=2>x = arround 33.69xxxxx (i needs to have 
+0.163)</FONT></FONT></DIV></DIV>
<DIV><FONT face=Arial size=2>so that when powered it equals 86.</FONT></DIV>
<DIV>&nbsp;</DIV>
<DIV><FONT face=Arial size=2><BR>---<BR>Outgoing mail is certified Virus 
Free.<BR>Checked by AVG anti-virus system (<A 
href="http://www.grisoft.com">http://www.grisoft.com</A>).<BR>Version: 6.0.551 /

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2. Re: what am i doing wrong here.

On Tue, 16 Dec 2003 17:05:38 +1100, Hayden McKay <hmck1 at dodo.com.au>
wrote:

>x = 86.0001776 - d -- x = 0.0001776
>x = i - d -------------- x = 1.776461434e-005 -- why?

Those two numbers are the same, just printed differently.

Try using printf(1,"%1.7f\n",{x}) instead.

>I'm trying to do this so I can get the root of x 
>and subtract it from c so that 
>c powerd again will equal ~exactly 86.

This might be what you're after:

function root(atom r, integer x)
	return power(2.718281828,log(r)/x)
end function

Any non-rational numbers will always be ~e-14 off.

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3. Re: what am i doing wrong here.

I found another way to get the any root of a number to 100% accuracy.
(below)

-- atom = root(atom digit, integer factor)
-- Calculate the root of a digit.
-- Returns the desired root.
global function root(atom a,integer n)
  a = power(a,(1/n))
  return a
end function




----- Original Message ----- 
From: "Pete Lomax" <petelomax at blueyonder.co.uk>
To: <EUforum at topica.com>
Sent: Tuesday, December 16, 2003 10:46 PM
Subject: Re: what am i doing wrong here.


>
>
> On Tue, 16 Dec 2003 17:05:38 +1100, Hayden McKay <hmck1 at dodo.com.au>
> wrote:
>
> >x = 86.0001776 - d -- x = 0.0001776
> >x = i - d -------------- x = 1.776461434e-005 -- why?
>
> Those two numbers are the same, just printed differently.
>
> Try using printf(1,"%1.7f\n",{x}) instead.
>
> >I'm trying to do this so I can get the root of x
> >and subtract it from c so that
> >c powerd again will equal ~exactly 86.
>
> This might be what you're after:
>
> function root(atom r, integer x)
> return power(2.718281828,log(r)/x)
> end function
>
> Any non-rational numbers will always be ~e-14 off.
>
>
>
> TOPICA - Start your own email discussion group. FREE!
>
>
> -- 
> Incoming mail is certified Virus Free.
> Checked by AVG anti-virus system (http://www.grisoft.com).
> Version: 6.0.551 / Virus Database: 343 - Release Date: 12/12/03
>


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