Re: Print a sequence (Phix)
- Posted by lib9 in February
- 330 views
petelomax said...
lib9 said...
formats in fmt are applied to successive elements.
You've only got one format, and it is applying that to the first element of args. You're just missing some {}.
sequence s = {"line 1", "line 2", "line 3", "line 4"} printf(1, "s: %V\n", {s}) -- extra parenthesis sequence buffer = {} for i = 1 to length(s) do printf(1, "l: %s\n", s[i]) buffer = append(buffer, s[i]) end for printf(1, "buffer1: %v\n", {buffer}) -- {} and %s->%v printf(1, "buffer2: %t\n\n", string(buffer)) -- print a bool
Thank you very much, Pete. I though that s and buffer were already declared as sequences so it wasn't needed to use the pair of braces in the printf statement.
Regarding Discord, I don't use as they ask for a phone number for identification and I don't want to give them that.
