1. delay loop
Please, could anyone with cpu over 1000mhz. tell me the output of the following?
... 3515 on P166.
--
include get.e
atom tick,ti,z,x tick=0 ti=time()
while time()-ti < .5 do
tick+=1 z=power(56.982,7.3)/tick
end while
function abs(object a)
if a<0 then return-a else return a end if
end function
procedure soft_delay()
for i = 1 to 2 + abs(tick/2400) do
z=power(56.982,7.3)/i end for
end procedure
x=0 ti=time()
while time()-ti < 5 do
soft_delay() soft_delay()
x += 1 end while
printf(1,"%d %s\n",{x/5,":done, any key exits"})
z=wait_key()
--
TIA, Wolf
2. Re: delay loop
- Posted by dm31 at uow.edu.au
May 17, 2002
>Please, could anyone with cpu over 1000mhz. tell me the output of the
following?
>... 3515 on P166.
>
I'm and AMD 1000mhz
i get 15889
Dan McGrath
3. Re: delay loop
----- Original Message -----
From: "Wolf" <wolfritz at KING.IGS.NET>
To: "EUforum" <EUforum at topica.com>
Subject: delay loop
>
> Please, could anyone with cpu over 1000mhz. tell me the output of the
following?
> ... 3515 on P166.
>
> --
I got 14821 on a Pentium III, 550mHz
4. Re: delay loop
- Posted by rubis at fem.unicamp.br
May 17, 2002
3382, under AMD 800, win XP (exw)
Rubens
At 01:06 17/5/2002, you wrote:
>
>Please, could anyone with cpu over 1000mhz. tell me the output of the
>following?
>... 3515 on P166.
>
>--
>include get.e
>atom tick,ti,z,x tick=0 ti=time()
>while time()-ti < .5 do
>tick+=1 z=power(56.982,7.3)/tick
>end while
>function abs(object a)
>if a<0 then return-a else return a end if
>end function
>procedure soft_delay()
>for i = 1 to 2 + abs(tick/2400) do
>z=power(56.982,7.3)/i end for
>end procedure
>x=0 ti=time()
>while time()-ti < 5 do
>soft_delay() soft_delay()
>x += 1 end while
>printf(1,"%d %s\n",{x/5,":done, any key exits"})
>z=wait_key()
>--
>TIA, Wolf
>
>
>
5. Re: delay loop
- Posted by rubis at fem.unicamp.br
May 17, 2002
18500/19700 AMD 800 , DOS, (ex)
At 01:06 17/5/2002, you wrote:
>
>Please, could anyone with cpu over 1000mhz. tell me the output of the
>following?
>... 3515 on P166.
>
>--
>include get.e
>atom tick,ti,z,x tick=0 ti=time()
>while time()-ti < .5 do
>tick+=1 z=power(56.982,7.3)/tick
>end while
>function abs(object a)
>if a<0 then return-a else return a end if
>end function
>procedure soft_delay()
>for i = 1 to 2 + abs(tick/2400) do
>z=power(56.982,7.3)/i end for
>end procedure
>x=0 ti=time()
>while time()-ti < 5 do
>soft_delay() soft_delay()
>x += 1 end while
>printf(1,"%d %s\n",{x/5,":done, any key exits"})
>z=wait_key()
>--
>TIA, Wolf
>
>
>
6. Re: delay loop
this seems strange to me...
17950 AMD 1000 Athlon under Windows ME
but then.. same machine booted into Linux Mandrake 8.3
4188!
Can anyone tell me explain this discrepancy?
Ken Rhodes
> At 01:06 17/5/2002, you wrote:
> >
> >Please, could anyone with cpu over 1000mhz. tell me
> the output of the
> >following?
> >... 3515 on P166.
> >
> >--
> >include get.e
> >atom tick,ti,z,x tick=0 ti=time()
> >while time()-ti < .5 do
> >tick+=1 z=power(56.982,7.3)/tick
> >end while
> >function abs(object a)
> >if a<0 then return-a else return a end if
> >end function
> >procedure soft_delay()
> >for i = 1 to 2 + abs(tick/2400) do
> >z=power(56.982,7.3)/i end for
> >end procedure
> >x=0 ti=time()
> >while time()-ti < 5 do
> >soft_delay() soft_delay()
> >x += 1 end while
> >printf(1,"%d %s\n",{x/5,":done, any key exits"})
> >z=wait_key()
> >--
> >TIA, Wolf
> >
> >
>
>
>
>
__________________________________________________
Do You Yahoo!?
LAUNCH - Your Yahoo! Music Experience
http://launch.yahoo.com
8. Re: delay loop
> this seems strange to me...
> 17950 AMD 1000 Athlon under Windows ME
> but then.. same machine booted into Linux Mandrake 8.3
> 4188!
Thank's everyone, but I'm still 'stupid'.
My first loop just checks the cpu speed, and the second was supposed to
compensate, so it was a *lot* closer to the same
on any machine. Guess I got it wrong in every way :(
Perhaps changing:
> > >for i = 1 to 2 + abs(tick/2400) do
to:
for i = 1 to (1 + (power(tick,1.2)/22000)) do
... might get a little closer ???
486/90 = 2360
P166 = 3330
The real number's not critical, as long as it doesn't go over 80,000 on an AMD
10,000 
Wolf
9. Re: delay loop
Hello Ken:
----------
> Îò: Ken Rhodes <ken_rhodes30436 at yahoo.com>
> Êîìó: EUforum <EUforum at topica.com>
> Òåìà: Re: delay loop
> Äàòà: ïÿòíèöà, Ìàé 17, 2002 22:17
>
> this seems strange to me...
> 17950 AMD 1000 Athlon under Windows ME
>
> but then.. same machine booted into Linux Mandrake 8.3
> 4188!
>
> Can anyone tell me explain this discrepancy?
>
> Ken Rhodes
I think, Linux has more clever multitasking than
Windows ME has.
Then Mandrake 8.3 is optimized just for Athlon,
it seems to be.
I have disks with RH 7.2, it is optimized for Athlon.
What is this optimisation? Partly it may be just a kind
of the soft delays (like Wolf's procedure) for the old software to make it
more similar (for user) to itself
on the old CPUs.
To have more clear picture with the real *performance*
in this case, you can try to run 3...4 separate processes with Wolf's
soft_delay() on your Athlon under Linux.
Just some thoughts, I do not know exactly.
New CPUs have extra power for most of the usual tasks
supported with the old software, I think.
Old CPUs are slow now, yes, but good and the best old
software may to look 'extra' fast now, on new CPUs.
Regards,
Igor Kachan
kinz at peterlink.ru
10. Re: delay loop
- Posted by a.tammer at hetnet.nl
May 17, 2002
Hello Wolf,
I timed it on a 1.7Ghz P4
3225 under WinMe,
23329 in a WinMe Dosbox
antoine tammer
a.tammer at hetnet.nl
11. Re: delay loop
- Posted by orr_kenneth at yahoo.ca
May 17, 2002
>> > >for i = 1 to 2 + abs(tick/2400) do
>to:
>for i = 1 to (1 + (power(tick,1.2)/22000)) do
>
>.... might get a little closer ???
>486/90 = 2360
>P166 = 3330
>
On my P100 Win98 laptop I get:
ewx = 4795
ex (DOS box) = 3619
ex (plain DOS) = 4069
On a old IBM 386DX/25 running DOS I get 157. 
_________________________________________________________
Do You Yahoo!?
Get your free @yahoo.com address at http://mail.yahoo.com
12. Re: delay loop
11637 400Mhz Celeron w/29 process runing.
Alvin
=====
See my homepage at
http://ka9qlq.tripod.com/home/
and where I live at
http://ka9qlq.tripod.com/CCC/
This is a 256 Megabyte 400 Mhz 13 Gig. plug and pray system.
__________________________________________________
Do You Yahoo!?
LAUNCH - Your Yahoo! Music Experience
http://launch.yahoo.com
13. Re: delay loop
Pentium4 1.8Ghz
873
Wolf wrote:
>
>Please, could anyone with cpu over 1000mhz. tell me the output of the
>following?
>... 3515 on P166.
>
>--
>include get.e
>atom tick,ti,z,x tick=0 ti=time()
>while time()-ti < .5 do
>tick+=1 z=power(56.982,7.3)/tick
>end while
>function abs(object a)
>if a<0 then return-a else return a end if
>end function
>procedure soft_delay()
>for i = 1 to 2 + abs(tick/2400) do
>z=power(56.982,7.3)/i end for
>end procedure
>x=0 ti=time()
>while time()-ti < 5 do
>soft_delay() soft_delay()
>x += 1 end while
>printf(1,"%d %s\n",{x/5,":done, any key exits"})
>z=wait_key()
>--
>TIA, Wolf
>
>
>
>
14. Re: delay loop
Sorry I forgot to add Win 98 OSR1 DOS box
Alvin
=====
See my homepage at
http://ka9qlq.tripod.com/home/
and where I live at
http://ka9qlq.tripod.com/CCC/
This is a 256 Megabyte 400 Mhz 13 Gig. plug and pray system.
__________________________________________________
Do You Yahoo!?
LAUNCH - Your Yahoo! Music Experience
http://launch.yahoo.com
15. Re: delay loop
Ken Rhodes wrote:
> but then.. same machine booted into Linux Mandrake 8.3
> 4188!
Do you mean 8.2, or did I miss a release?
-- David Cuny
16. Re: delay loop
OOPS! it is in fact Mandrake 8.2 :)
Ken Rhodes
--- David Cuny <dcuny at LANSET.COM> wrote:
>
> Ken Rhodes wrote:
>
> > but then.. same machine booted into Linux Mandrake
> 8.3
> > 4188!
>
> Do you mean 8.2, or did I miss a release?
>
> -- David Cuny
>
>
>
>
>
>
17. Re: delay loop
EX: 4783
EXW: 1755
With PEU recompiled with BCC I get 858993459. But this seems to be a bug :)
Winchip 200 Mhz
Martin
> Please, could anyone with cpu over 1000mhz. tell me the output of the
> following?
> ... 3515 on P166.
>
> --
> include get.e
> atom tick,ti,z,x tick=0 ti=time()
> while time()-ti < .5 do
> tick+=1 z=power(56.982,7.3)/tick
> end while
> function abs(object a)
> if a<0 then return-a else return a end if
> end function
> procedure soft_delay()
> for i = 1 to 2 + abs(tick/2400) do
> z=power(56.982,7.3)/i end for
> end procedure
> x=0 ti=time()
> while time()-ti < 5 do
> soft_delay() soft_delay()
> x += 1 end while
> printf(1,"%d %s\n",{x/5,":done, any key exits"})
> z=wait_key()
> --
> TIA, Wolf
18. Re: delay loop
On 17 May 2002, at 0:06, Wolf wrote:
>
> Please, could anyone with cpu over 1000mhz. tell me the output of the
> following? ... 3515 on P166.
>
> --
> TIA, Wolf
>
Wolf:
No GHz here though I got some strange values:
1. Intel Pentium MMX 200MHz running Windows98SE
loop.ex
run 1 = 3604
2 = 3878
3 = 3501 (3552.5 avg.)
loop.exw
run 1 = 2423
2 = 3084
3 = 3899 (3135.3 avg.)
2. Intel 486 DX2 66MHz running WindowsNT4/sp6
loop.ex
run 1 = 569
2 = 532
3 = 531 (544.0 avg.)
loop.exw
run 1 = 2383
2 = 3091
3 = 2383 (2619.0 avg.)
Looks that ex.exe (or loop.ex) don't like 486s, at least as much as
exw.exe (or loop.exw) do.
I also run sieve.ex on 486 and than sieve.exw with these following
results:
3. Intel 486 DX2 66MHz running WindowsNT4/sp6
sieve.ex
run 1 = 637.9 sieves
2 = 640.0 sieves
3 = 641.2 sieves (639.7 sieves avg.)
loop.exw
run 1 = 650.0 sieves
2 = 651.2 sieves
3 = 651.2 sieves (650.8 sieves avg.)
Pretty much the same, huh? Any clues?
Be good,
-- Euler
--
19. Re: delay loop
> No GHz here though I got some strange values:
I got similar strange results between 486/90 and P166, all in DOS box, however
my 486 still has EU 2.2 !
P166 .exw > 3521 .ex > 6898
486/90 .exw > 1956 .ex > 1102
.. in pure DOS this was still only 1746.
.btw, in case anyone's interested, I solved my problem with:
for i = 1 to (2 + (floor(power(tick,1.1))/20000)) do
.. which gave counts of 6690 on a P166, and only 7230 on a Duron950, using .exw
.. not much difference, close enuf :)
20. Re: delay loop
- Posted by r.schr at t-online.de
May 19, 2002
"Wolf" <wolf- at KING.IGS.NET> wrote:
> Please, could anyone with cpu over 1000mhz. tell me the output of the
> following?
> ... 3515 on P166.
I'm still with my 400 MHz AMD, and I'm also somewhat late, but this
are my results:
WinNT, under cmd.exe, with ex.exe:
796 :done, any key exits
806 :done, any key exits
809 :done, any key exits
799 :done, any key exits
WinNT, under cmd.exe with exw.exe:
3226 :done, any key exits
3268 :done, any key exits
3219 :done, any key exits
3167 :done, any key exits
MS-DOS 6.22:
11168 :done, any key exits
10325 :done, any key exits
10327 :done, any key exits
11278 :done, any key exits
Have a nice day, Rolf
(-:
