OpenEuphoria

Re: delay loop

• Posted by rubis at fem.unicamp.br May 17, 2002
• 456 views

18500/19700 AMD 800 , DOS, (ex)

At 01:06 17/5/2002, you wrote:
>
>Please, could anyone with cpu over 1000mhz. tell me the output of the 
>following?
>... 3515 on P166.
>
>--
>include get.e
>atom tick,ti,z,x tick=0 ti=time()
>while time()-ti < .5 do
>tick+=1 z=power(56.982,7.3)/tick
>end while
>function abs(object a)
>if a<0 then return-a else return a end if
>end function
>procedure soft_delay()
>for i = 1 to 2 + abs(tick/2400) do
>z=power(56.982,7.3)/i end for
>end procedure
>x=0 ti=time()
>while time()-ti < 5 do
>soft_delay() soft_delay()
>x += 1 end while
>printf(1,"%d %s\n",{x/5,":done, any key exits"})
>z=wait_key()
>--
>TIA, Wolf
>
>
>