delay loop
- Posted by Wolf <wolfritz at KING.IGS.NET> May 16, 2002
- 472 views
Please, could anyone with cpu over 1000mhz. tell me the output of the following? ... 3515 on P166. -- include get.e atom tick,ti,z,x tick=0 ti=time() while time()-ti < .5 do tick+=1 z=power(56.982,7.3)/tick end while function abs(object a) if a<0 then return-a else return a end if end function procedure soft_delay() for i = 1 to 2 + abs(tick/2400) do z=power(56.982,7.3)/i end for end procedure x=0 ti=time() while time()-ti < 5 do soft_delay() soft_delay() x += 1 end while printf(1,"%d %s\n",{x/5,":done, any key exits"}) z=wait_key() -- TIA, Wolf