OpenEuphoria

routine_id() Discovery

• Posted by c.k.lester <euphoric at ckle?ter.c?m> May 21, 2008
• 695 views

Maybe this is common knowledge, but I just discovered this...

A routine doesn't have to be global in order to call it from what would
otherwise require a global definition.

For example, this would normally fail:

-- mylib.e
func myfunc()
end func

-- myprog.e
x = myfunc()

with myfunc() is not defined (I think).

But, if I add the routine_id() of myfunc() to a global list, then I can
call it from myprog.e with call_func().

That means it can be exported but not made global... right?