OpenEuphoria

RE: Standard Euphoria Library Project

• Posted by Brian Broker <bkb at cnw.com> Feb 07, 2001
• 568 views

FYI: this is straight out of our friendly refman doc:

You can delete element i of any sequence s by concatenating the parts of 
the sequence before and after i: 

	s = s[1..i-1] & s[i+1..length(s)]

This works even when i is 1 or length(s), since s[1..0] is a legal empty 
slice, and so is s[length(s)+1..length(s)]. 

(see sections 2.2.6 and 2.2.7)

-- Brian

Chris Bensler wrote:
> DOH!!
> Don't think I actually ever TRIED to see if it works or not before!!
> 
> To me it just seems irrational that it WOULD work.. it's an invalid 
> subscript..
> 
> But to my amazement it does!!
> 
> Foolish me..
> 
> Chris {;oP DUH!
> 
> Chris Bensler wrote:
> > You shouldn't be allowed to try and access an out of bounds subscript..
> > It may not crash, but why would you want it to do that? IMHO, it should 
> > crash.. that's what error checking is for..
> > 
> > Chris
> > 
> > Fam. Nieuwenhuijsen wrote:
> > > > David Cuny wrote:
> > > >
> > > >   <SNIP>
> > > > > function remove( integer i, sequence s)
> > > > > -- remove ith element from s
> > > > >     return s[1..i-1] & s[i+1..length(s)]
> > > > > end function
> > > >    <SNIP>
> > > >
> > > > What if the user tries to remove the first or last item?
> > > > i would end up being 0 or greater than the length of >the sequence..
> > > 
> > > Yes, *but* Euphoria won't crash. When you slice from one above the 
> > > length of
> > > the sequence or when you slice to zero it will return an empty seq 
> > > rather
> > > than crash.
> > > 
> > > Come on people. This is trivial beginners stuff.
> > > 
> > > Ralf N.
> > > nieuwen at xs4all.nl