OpenEuphoria

Re[2]: About atom memories

• Posted by aku saya <akusaya at gmx.net> Feb 25, 2003
• 393 views

OK, thanks!

Second test:

object x
x = rand(repeat(100000, 10*1024*1024))
? x[1]
x = getc(0)
x = rand(repeat(100000, 20*1024*1024))
x = getc(0)

When length(x) = 10MB, memory usage is  82276 KB ~~  80.3 MB
When length(x) = 20MB, memory usage is 164196 KB ~~ 160.3 MB

so 1 atom = 8 byte??? not 4 byte in this case???


And I found that x[1] is always about 80000 < x[1] < 90000,
not 0 < x[1] <= 100000 as I expected.
A bug in rand() function?

______________________________________________

R> Aku writes:
>> object x
>> for i = 1024*1024 to 1000000000000000000000 by 1024*1024 do
>>    x = repeat(i+111111111.111111111111111111111111111111111, i)
>>    ? i
>>    printf(1, "%20.20f\n", x[i])
>>    x = getc(0)
>> end for
>>
>> after i = 10MB, I saw the memory usage (using TaskInfo2000),
>> it was 41376 KB ~~ 40.4 MB
>>
>> So one atom just use 4 bytes, not 8 bytes?
>> And the precision is still 16 digits!

R> When i is 10 million, x will have 10 million 4-byte pointers to
R> a single floating-point value.

R> Regards,
R>    Rob Craig
R>    Rapid Deployment Software
R>    http://www.RapidEuphoria.com



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