1. Re[2]: About atom memories
OK, thanks!
Second test:
object x
x = rand(repeat(100000, 10*1024*1024))
? x[1]
x = getc(0)
x = rand(repeat(100000, 20*1024*1024))
x = getc(0)
When length(x) = 10MB, memory usage is 82276 KB ~~ 80.3 MB
When length(x) = 20MB, memory usage is 164196 KB ~~ 160.3 MB
so 1 atom = 8 byte??? not 4 byte in this case???
And I found that x[1] is always about 80000 < x[1] < 90000,
not 0 < x[1] <= 100000 as I expected.
A bug in rand() function?
______________________________________________
R> Aku writes:
>> object x
>> for i = 1024*1024 to 1000000000000000000000 by 1024*1024 do
>> x = repeat(i+111111111.111111111111111111111111111111111, i)
>> ? i
>> printf(1, "%20.20f\n", x[i])
>> x = getc(0)
>> end for
>>
>> after i = 10MB, I saw the memory usage (using TaskInfo2000),
>> it was 41376 KB ~~ 40.4 MB
>>
>> So one atom just use 4 bytes, not 8 bytes?
>> And the precision is still 16 digits!
R> When i is 10 million, x will have 10 million 4-byte pointers to
R> a single floating-point value.
R> Regards,
R> Rob Craig
R> Rapid Deployment Software
R> http://www.RapidEuphoria.com
R> TOPICA - Start your own email discussion group. FREE!
