RE: Repeat efficiency
- Posted by Andy Serpa <ac at onehorseshy.com> Feb 19, 2003
- 461 views
> > > > e = time() m = 4 * 768 * 1024 > > z = allocate(m) > > mem_set(z, m, 0) The 2nd & 3rd terms of mem_set look inverted here.
> > > > e = time() m = 4 * 768 * 1024 > > z = allocate(m) > > mem_set(z, m, 0) The 2nd & 3rd terms of mem_set look inverted here.