Re: Defeating Murphy's laws and a new challenge
On Fri, 18 Apr 2003 23:00:17 -0300, rforno at tutopia.com wrote:
>Pete:
>What is the value for 'a' in Data[Lendata]+=3D2*a+1 ?
My apologies. I was updating the wrong ends of the array which is why
it defeated all the optimisations. Sorry. I take it all back, I can't
find a data set which messes it up either 
One small point: if the highest value in the array is a partition all
by itself, eg {111,9,9,9,9,9,5,1,1,1}, then the partitions are
correctly printed but BestVal is zero.
Pete
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Not Categorized, Please Help
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