Re: Increment Sequence values

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--Boundary_(ID_HAzAPlvYlKoMi7kSaytTCA)


  ----- Original Message ----- 
  From: tuncaydin6 at tuncaydin6.screaming.net 
  To: EUforum 
  Sent: Wednesday, March 07, 2001 6:17 PM
  Subject: Increment Sequence values


  Hi!!
   
If I have a sequence and want to use each element in the sequence one at a
  time how would I do this?

  What is the increment operator?
  ++?
  eg:
  x[1]++?
  x[1+1]?
  help!!

If you want to use a single element, refer to it as x[n] where n = 1.. length
  of x
  given x = {1,3,5,9},    x[3] will be 5
  x[3] += 1   adds one to the third element, giving {1,3,6,9}
  x += 1 adds one to each element, giving {2,4,6,10}
  if you want to do something with each element, make a loop:
  for n = 1 to lenght(x) do
    something with x[n]
  end for.

  Regards,
  Irv


--Boundary_(ID_HAzAPlvYlKoMi7kSaytTCA)

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  <DIV style="FONT: 10pt arial">----- Original Message ----- </DIV>
  <DIV 
  style="BACKGROUND: #e4e4e4; FONT: 10pt arial; font-color: black"><B>From:</B> 
  <A href="mailto:tuncaydin6 at tuncaydin6.screaming.net" 
title=tuncaydin6 at tuncaydin6.screaming.net>tuncaydin6 at
  tuncaydin6.screaming.net</A>
  </DIV>
<DIV style="FONT: 10pt arial"><B>To:</B> <A href="mailto:EUforum at
  topica.com"
  title=EUforum at topica.com>EUforum</A> </DIV>
  <DIV style="FONT: 10pt arial"><B>Sent:</B> Wednesday, March 07, 2001 6:17 
  PM</DIV>
  <DIV style="FONT: 10pt arial"><B>Subject:</B> Increment Sequence values</DIV>
  <DIV><BR></DIV>
  <DIV><FONT face=Arial size=2>Hi!!</FONT></DIV>
  <DIV><FONT face=Arial size=2></FONT>&nbsp;</DIV>
<DIV><FONT face=Arial size=2>If I have a sequence and want to use each element
  in the sequence one at a time how would I do this?</FONT></DIV>
  <DIV>&nbsp;</DIV>
  <DIV><FONT face=Arial size=2>What is the increment operator?</FONT></DIV>
  <DIV><FONT face=Arial size=2>++?</FONT></DIV>
  <DIV><FONT face=Arial size=2>eg:</FONT></DIV>
  <DIV><FONT face=Arial size=2>x[1]++?</FONT></DIV>
  <DIV><FONT face=Arial size=2>x[1+1]?</FONT></DIV>
  <DIV><FONT face=Arial size=2>help!!</FONT></DIV>
  <DIV>&nbsp;</DIV>
  <DIV><FONT face=Arial size=2>If you want to use a single element, refer to it 
  as x[n] where n = 1.. length of x</FONT></DIV>
  <DIV><FONT face=Arial size=2>given x = {1,3,5,9},&nbsp;&nbsp;&nbsp; x[3] will 
  be 5</FONT></DIV>
  <DIV><FONT face=Arial size=2>x[3] += 1&nbsp;&nbsp; adds one to the third 
  element, giving {1,3,6,9}</FONT></DIV>
  <DIV><FONT face=Arial size=2>x += 1 adds one to each element, giving 
  {2,4,6,10}</FONT></DIV>
  <DIV><FONT face=Arial size=2>if you want to do something with each element, 
  make a loop:</FONT></DIV>
  <DIV><FONT face=Arial size=2>for&nbsp;n = 1 to lenght(x) do</FONT></DIV>
  <DIV><FONT face=Arial size=2>&nbsp; something with x[n]</FONT></DIV>
  <DIV><FONT face=Arial size=2>end for.</FONT></DIV>
  <DIV>&nbsp;</DIV>
  <DIV><FONT face=Arial size=2>Regards,</FONT></DIV>
  <DIV><FONT face=Arial size=2>Irv</FONT></DIV>
  <DIV>&nbsp;</DIV></BLOCKQUOTE>
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