OpenEuphoria

Re: Integer() operation on a sequence?

• Posted by "Elliott S. de Andrade" <quantum_analyst at hotmail.com> Jun 06, 2004
• 456 views

>From: Derek Parnell <guest at RapidEuphoria.com>
>Reply-To: EUforum at topica.com
>To: EUforum at topica.com
>Subject: Re: Integer() operation on a sequence?
>Date: Sat, 05 Jun 2004 18:02:04 -0700
>
>Michael Raley wrote:
> > not too suprisingly I cannot do this
> >
> >  s =  integer({0.12321,0.44343,1,1,0.555})
> > - s becomes {0,0,1,1,0}
>

That is not what integer() is for. Obviously, you cannot do that.

>What were you expecting to achieve?
>
>** Did you wish to convert each of the elements into an integer?
>   seq s s = floor({0.12321,0.44343,1,1,0.555})
>
>** Did wish to see if each element was an integer?
>   seq s s = integer({0.12321,0.44343,1,1,0.555})
>

  You'd need a for-loop for that one, Derek. You'll get a type-check error 
because integer() will return 0.

>** Did you wish to see if the entire paramter was an integer?
>   integer s if integer({0.12321,0.44343,1,1,0.555}) then
>     s = 1 else s = 0 end if
>
>** Did you wish to convert the entire parameter into a single integer?
>     sequence s s = value({0.12321,0.44343,1,1,0.555})
>
Uh... What?

>
>
> >  So howabout?
> >  s = integers({sequence})
>
>What is supposed to return? The number of integers in the sequence?
>
>    s = integer (x)
>    y = 0
>    for i = 1 to length(x)
>         y += x[i]
>    end for
>
That would give you the sum of the values in the sequence. I'm not sure what 
s if for either. You mean:

y = 0
for i = 1 to length(x) do
    y += integer(x[i])
end for

> >  Secondly; a sequence summation operator
> >  i= ~sigma ({sequence s from above})
> >  i = 2
>
  Don't use the tilde! I wanted that for ignoring return values of 
functions. That's a whole other topic which could be discussed in another 
thread. As Derek said, though, you don't need a new operator for such a 
thing.

>
[stuff written that I didn't comment on]
>

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