OpenEuphoria

Re: What is up with the 'FIND' function?

• Posted by ZNorQ <znorq at holhaug.com> Mar 23, 2006
• 555 views

Well, seems that the match works out the way I wanted to anyway!

Thanks again! :)



Patrick Barnes wrote:
> 
> wait, nevermind... that's not right:
> 
> 
> constant haystack1 = { {1}, {2}, {3}, {4}, {5}, {6} }
> constant haystack2 = { 1, 2, 3, 4, 5, 6 }
> constant needle1 = {3}
> constant needle2 = 3
> 
> ? find( needle1, haystack1 ) -- 3
> ? match( needle1, haystack1 ) -- 0
> ? find( needle1, haystack2 ) -- 0
> ? match( needle1, haystack2 ) -- 3
> ? find( needle2, haystack1 ) -- 0
> ? match(needle2, haystack1 ) -- 0
> ? find( needle2, haystack2) -- 3
> ? match(needle2, haystack2) --0
> 
> Does that make more sense?
> 
> 
> On 3/23/06, Patrick Barnes <mrtrick at gmail.com> wrote:
> >
> > You are confusing find() and match()...
> > find() searches a sequence looking for an element...
> > constant haystack1 = { {1}, {2}, {3}, {4}, {5}, {6} }
> > constant haystack2 = { 1, 2, 3, 4, 5, 6 }
> > constant needle1 = {3}
> > constant needle2 = 3
> >
> > ? find( needle1, haystack1 ) --finds {3} within haystack1, prints 3
> > ? match( needle2, haystack2 ) --finds a slice of haystack2 matching
> > needle2, prints 3
> >
> > all other combinations will return 0.
> >
> >
> > On 3/23/06, ZNorQ <guest at rapideuphoria.com> wrote:
> > >
> > >
> > > posted by: ZNorQ <znorq at holhaug.com>
> > >
> > > Hey,
> > >
> > > I'm trying to get the 'FIND' function to use properly, but I just don't
> > > get it to work the way I want it to.
> > >
> > > I have a string called zALPHA, containing all the letters in both upper
> > > and lower case;
> > >
> > > constant zALPHA = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWX=
> YZ"
> > >
> > > Further, I have a sequence - 'eRevision' - which contains a letter in t=
> he
> > > above range (Hence, the eRevision is of length 1, but still a sequence.=
> ).
> > >
> > > Lets say the eRevision sequence contains 'c', I'd think that the follow=
> ing
> > > function should return '3', but it returns '0' (Zero);
> > >
> > > eFindResult = find(eRevision, zALPHA)
> > >
> > > ..while THIS function returns the correct number;
> > >
> > > EFindResult = find(eRevision[1], zALPHA)
> > >
> > > Could someone please explain this to me?
> > >
> > > Regards, Kenneth 'ZNorQ' Nilsson
> > >
> > >
> > --
> > MrTrick
> > ----------
> >
> >
> --
> MrTrick
> ----------
> 
>