OpenEuphoria

Where is my DLL?

• Posted by "Juergen Luethje" <j.lue at gmx.de> Oct 15, 2005
• 756 views

Hi all,

how can a DLL find the path where it was loaded from?
I need it because the DLL must read an INI file that is in the same
directory as the DLL. Of course I don't know, where the users will
install it.

command_line() is of no use here, because when calling it from a DLL the
return value obviously is an empty sequence.
The Win32 API function GetModuleFileName() came to my mind. But if I
pass NULL to it as the module handle parameter, the function returns
the path of the EXE file that has called the DLL.

Somewhere on the internet I read:
| If you want to find the path for a DLL, pass the DLLs instance handle,
| which you can obtain from the first parameter in your DLL's DLLMain()
| function.

Of course in Euphoria there is no DLLMain() function.
When I pass the result of Euphoria's instance() function as the module
handle parameter, GetModuleFileName() also returns the path of the EXE
file instead the path of the DLL.

Then I found the API function GetModuleHandle(). This gives me the
handle of a module, so that I can find its name. As parameter,
GetModuleHandle() requires the name of the module ... )

Well, that name does not have to specify a path, so this might work to
some degree. E.g. I can pass "my.dll" to GetModuleHandle(), than pass
the handle to GetModuleFileName(), and as result I'll get e.g.
"C:\this\and\that\my.dll".

This not only seems somewhat crazy to me , I think there can be at
least two problems:
a) If the user renames the DLL, GetModuleHandle() will not return its
   handle any more.

b) If the name does not include a path and there is more than one
   loaded module with the same base name and extension, you cannot
   predict which module handle will be returned.
   [MSDN Library]


What can I do? Thanks in advance for any hints.

Regards,
   Juergen

-- 
Have you read a good program lately?