OpenEuphoria

Re: [E - 19 to 20 May 1998 (#1998-7)] Command Line Length

• Posted by Terry Constant <constant at FLASH.NET> May 24, 1998
• 725 views

Jeff,
Thanks for the reply.

Yes, Euphoria crashes before it ever starts. And crashes badly. You
probably missed a previous reply to Robert in which I attached the
Cw.err that is created. It is a long and nasty looking document.

Thanks for the code snippet. If it looks like I will have to use this
workaround, it will save some time. Sometime in the near future I will
work with it, regardless. If I turn up something interesting or come up
with a worthy enhancement to it, I will report back to you.

Again, thanks.

Jeff Zeitlin wrote:
>
> On Sat, 23 May 1998 00:00:02 -0400, Terry Constant
> <constant at FLASH.NET> wrote:
>
> >1. For the information to be in CMDLINE, the information has to be on
> >the command line that calls the Euphoria program. When this command line
> >gets bigger than 128, Euphoria crashes. There is not a way to get the
> >long line in CMDLINE without crashing the Euphoria program.
>
> I see; I misunderstood - your program is crashing on entry, not
> when you call command_line(), is that correct?  I thought
> otherwise.  You are, however, correct about the relationship
> between CMDLINE and program execution; I apologize for my
> misapprehension.
>
> >2. However, you sparked an idea in me. I could assign the arguments of a
> >long command line to any variable I choose. But then I would have to
> >parse the line instead of it already being in a nice and neat sequence
> >for me. All in all, I could do it, but this is a real kludge work
> >around. But, if all else fails, this idea that you sparked would work.
>
> The following function (untested) might help - it takes any
> sequence that has spaces in it and returns a sequence of
> sequences, each item in the returned sequence being a "word" from
> the original sequence.
>
> function read_parse(sequence s)
>   sequence p
>   integer l
>
>   p = {}
>   while length(s) > 0
>     l = find(' ',s)
>     if l = 0 then
>       l = length(s) + 1
>     end if
>     p = append(p,s[1..l-1])
>     s = s[l..length(s)]
>     if length(s) > 0 then
>       s = s[2..length(s)]
>     end if
>   end while
>   return p
> end function
>
> If my brain ever starts functioning again, I'll make another cut
> at this, to handle quoted strings as well.
> --
> Jeff Zeitlin
> jeff.zeitlin at mail.execnet.com

--
Terry Constant
constant at flash.net