OpenEuphoria

Re: printf() on decimals

• Posted by Greg Haberek <g.haberek at comcast.net> Jun 30, 2003
• 592 views

> Try this:
>
> printf(1, "%.16g\n", 1999999999999990)
> printf(1, "%.16g\n", 2999999999999990)
> printf(1, "%.16g\n", 3999999999999990)
> printf(1, "%.16g\n", 4999999999999990)
> printf(1, "%.16g\n", 5999999999999990)
> printf(1, "%.16g\n", 6999999999999990)
> printf(1, "%.16g\n", 7999999999999990)
> printf(1, "%.16g\n", 8999999999999990)
> printf(1, "%.16g\n", 9999999999999990)
>
>
> Why is the last line printed differently?

ex.exe produced:

1999999999999990
2999999999999990
3999999999999990
4999999999999990
5999999999999990
6999999999999990
7999999999999990
8999999999999990
9999999999999990

however, exw.exe produced:

1999999999999990
2999999999999990
3999999999999990
4999999999999990
5999999999999990
6999999999999990
7999999999999990
8999999999999990
9.99999999999999e+015

i assume this has to do with how windows handles floating-point math as
opposed to dos and 'nix.