OpenEuphoria

RE: not_bits() not_working()

• Posted by Al Getz <Xaxo at aol.com> Jun 26, 2003
• 589 views

rolf at rschr.de wrote:
> 
> 
> Al Getz wrote:
>  
> > atom a,x
> > a=2
> >
> > x=not_bits(a)
> >
> > --now x equals -3, which isnt correct.
> 
> 
> It is correct! look at this (or try it yourself):
> ---------------------------------------------------
> printf(1,"%08x\n", 2 )			-- 00000002
> printf(1,"%08x\n", not_bits(2) )	-- FFFFFFFD
> ---------------------------------------------------
> 
> Please notice also:
> 
> 0000 0000 0000 0000 0000 0000 0000 0010 =  2 = #00000002
> 1111 1111 1111 1111 1111 1111 1111 1101 = -3 = #FFFFFFFD
> 
> Have a nice day, Rolf
> 

Hi Rolf, 

I think you will find that the results of the printf statement
using the '%x' hex formatter is very very misleading.
Just because it 'displays' the correct hex value doesnt mean
it's stored internally in a form that is correct for using
with the other _bit functions.  Strange for sure 
In order to be certain, you have to print the number out
two times: once using the '%x' formatter and once using the
'%d' formatter (or just '?').
Try that and note what the results are and how they differ.

Take care for now,
Al