Re: Leap Years
- Posted by Ad Rienks <Ad_Rienks at COMPUSERVE.COM> Mar 04, 1998
- 779 views
Craig wrote: >Nope. Just ran some tests; a division all by itself is still >slower than a remainder. That strikes me as really odd; doesn't >it have to divide anyway to _find_ the remainder? Oh, well. No, I think internally the machine only subtracts to find a remainder. Ad Rienks