Re: -Infinity / -Infinity
> At "A = 0 - A", we have a negative infinity. I understand that. Then "A / A"
> (i.e., -inf / -inf) is computed, resulting in a negative nan. Um... is this
> *supposed* to be the case with infinities? I would have thought that two
> negatives, even infinities, would result in a positive number (or not-a-number).
> Or is my higher math education incomplete?
I tried it on my computer and got the same results. A/A should be 1 as long as a
isn't 0 (in which case it's undefined), and it definately shouldn't be negitive.
There isn't any reason why -infinity/-infinity should equal -(not a number).
--
Jeffrey Fielding
JJProg at cyberbury.net
http://members.tripod.com/~JJProg/
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