OpenEuphoria

Re: find or equal test problem

• Posted by sixs <sixs at ida.net> May 26, 2005
• 400 views

Thanks for the advice from all. I am trying to find words in  a listing 
or letter document .
I can see how to find  a  comma in a line, but I was trying to find a 
word  like "pickle" in a line of information.  I have created  HTML 
code, found a single character ">" and then compared  what was in 
buffer[found location], length of expected value. I thought that I  
might find a simple way to do it. If you have any advice I would 
appreciate it!
Thanks
Jim

Derek Parnell wrote:

>
>
>posted by: Derek Parnell <ddparnell at bigpond.com>
>
>sixs wrote:
>  
>
>>Hi,
>>I can't figure what the pproblem is in this program. I try to find the 
>>letter "p"  in the sequence pp. I see that the value is 112 for p .
>>I have used the find and equal command before but  i don't know what i'm 
>>not doing
>>    
>>
>When you write a string in the form "xyz", you are actually coding a sequence
>of three integers. "xyz" is exactly the same as {'x', 'y', 'z'}.
>
>So with 
>
>  pp = { "pickle" }
>
>it is the same as 
>
>  pp = { {'p', 'i', 'c', 'k', 'l', 'e'} }
>
>thus the line 
>
>   location = find( "p", pp)
>
>is the same as 
>
>   location = find( {'p'}, { {'p', 'i', 'c', 'k', 'l', 'e'} })
>
>and as you can see, the variable pp does not contain an element that looks like
>{'p'} as it only contains one element and that is a sequence of six integers
>(letters).
>
>To find a single letter inside a string, use find like this ...
>
>   a = find('x', string)
>
>Note that the X is in single quotes and not double quotes, as that would mean
>you are looking for a string as *one* of the elements of the target.
>
>Try the amended code below ...
>
>}}}
<eucode>
>object line
>integer location
>
>procedure process()
> sequence pp
>
> pp = "pickle"
>
> location = find('p', pp)
> if equal(location, 1) then
>   line = pp
> else
>   line = "    " & pp
> end if
>end procedure
>process()
></eucode>
{{{

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