OpenEuphoria

Re: find or equal test problem

• Posted by Derek Parnell <ddparnell at bigpond.com> May 25, 2005
• 498 views

sixs wrote:
> 
> Hi,
> I can't figure what the pproblem is in this program. I try to find the 
> letter "p"  in the sequence pp. I see that the value is 112 for p .
> I have used the find and equal command before but  i don't know what i'm 
> not doing

When you write a string in the form "xyz", you are actually coding a sequence of
three integers. "xyz" is exactly the same as {'x', 'y', 'z'}.

So with 

  pp = { "pickle" }

it is the same as 

  pp = { {'p', 'i', 'c', 'k', 'l', 'e'} }

thus the line 

   location = find( "p", pp)

is the same as 

   location = find( {'p'}, { {'p', 'i', 'c', 'k', 'l', 'e'} })

and as you can see, the variable pp does not contain an element that looks like
{'p'} as it only contains one element and that is a sequence of six integers
(letters).

To find a single letter inside a string, use find like this ...

   a = find('x', string)

Note that the X is in single quotes and not double quotes, as that would mean
you are looking for a string as *one* of the elements of the target.

Try the amended code below ...

object line
integer location

procedure process()
 sequence pp

 pp = "pickle"

 location = find('p', pp)
 if equal(location, 1) then
   line = pp
 else
   line = "    " & pp
 end if
end procedure
process()

-- 
Derek Parnell
Melbourne, Australia
irc://irc.sorcery.net:9000/euphoria