Re: Math Problem - Probability of Password Duplication

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CK Lester wrote:

> > As far as I can see it would be:
> > result = power(89,11)+power(89,12)+power(89,13)+power(89,14)
>
> That comes to 1,978,642,898,134,390,000,000,000,000, according to MS
Excel.

bc under linux says 1,978,642,898,134,388,772,961,847,220, but Euphoria only
matches Excel in this regard. sad

Carl

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