Re: Fermat extended - Only for mathemathicians

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actually, there is a rather large book that details the proof ( that is, =
details of the steps taken to solve the problem ) of fermats theorem that=
 was written (I believe) in the nineties--I've never read the work myself=
, but I seen it referenced quite a few times.  If I can, I'll try to find=
 the title.

~Nathan
----- Original Message -----
From: rforno at tutopia.com
Subject: RE: Fermat extended - Only for mathemathicians


Apparently you did not read the caption at the top of the program, or my
English is very bad.
I know that this program cannot prove the conjecture to be true, but it c=
an
prove it to be false.
Moreover, I was interested in knowing if someone posed the same conjectur=
e
that I call "extended Fermat theorem".
About the original conjecture, I remember having heard that someone final=
ly
proved it to be true, not by means of a computer program but using advanc=
ed
math theory.
----- Original Message -----
From: <rswiston at hotmail.com>
To: EUforum <EUforum at topica.com>
Sent: Thursday, August 15, 2002 1:23 AM
Subject: Re: Fermat extended - Only for mathemathicians


>
> I think your information is incorrect.  Femat's theorem is only true si=
nce
> no one can find a value of p to make it false.  (Remember theorem means=
 a
> statement yet to be proven false).  To prove the theorem, one must prov=
ide
> proof that the "conjecture" is true for all values of p (not simply a f=
ew
> selected ones... and infinity is a pretty big number!).  Since this is
> nearly inpossible (I say nearly since super computers can do marvelous
> things these days) no one has yet to prove (or disprove) the theorem.
Your
> program can produce sums given a provided input from the variables, but
will
> still not "prove" the theorem.  It is simply looking for a value that w=
ill
> prove the theorem false (which may well happen if allowed to run long
> enough... in a loop that doesn't end until the proof has been found
invalid)
> and therefore does not prove the theorem.  (AUUGHH high school geometry
> rears its ugly head!).  Unfortunately, computer programs are designed
around
> numbers either set or inputed from a loop or user input.  They are not
> designed to act upon an unknown (do not confuse the term variable we
> mathmeticians use with the same term computer programmers use).
>
> -Robert
>
> ----- Original Message -----
> From: <rforno at tutopia.com>
> To: "EUforum" <EUforum at topica.com>
> Sent: Tuesday, August 13, 2002 10:08 PM
> Subject: Fermat extended - Only for mathemathicians
>
>
> > Dear EUphorians:
> > Apparently, someone proved the last theorem by Fermat to be true.
> > I don't know if the following extension to Fermat's theorem (or
> conjecture)
> > has ever be posed by someone, but here it is, with a program that tri=
es
to
> > find a counterexample. I've found no one yet.
> > Comments are welcome.
> >
> > -- Trying to find a counterexample for the "extended-Fermat conjectur=
e",
> > that
> > -- x[1]^p+x[2]^p...+x[n]^p =3D z^p, for x[i] > 0, 1 < n < p has no in=
teger
> > -- solutions.
> > -- Author R. M. Forno - Version 1.0 - 2002/08/13
> >
> > constant COMPL =3D 30 -- Start with numbers somewhat big
> > sequence top -- The elements
> >
> > procedure verify(integer n, integer p) -- Verify conjecture
> >     atom root, sum
> >     integer r
> >     sum =3D 0
> >     for i =3D 1 to n do -- Always perform the sum to avoid rounding e=
rrors
> >         sum +=3D power(top[i], p)
> >     end for
> >     root =3D power(sum, 1 / p)
> >     r =3D floor(root + 0.5) -- Beware of rounding errors
> >     if power(r, p) =3D sum then -- Show results... some day
> >         printf(1, "Power: %d Left: %f Right:", {p, root})
> >         for i =3D 1 to n do
> >             printf(1, " %d", top[i])
> >         end for
> >         puts(1, '\n')
> >     end if
> > end procedure
> >
> > procedure fermat()
> >     integer p, k, i, r
> >     p =3D 2
> >     while p <=3D 20 do
> >         p +=3D 1
> >         printf(1, "Testing exponent %d\n", p)
> >         r =3D p - 1
> >         for n =3D 2 to r - 1 do  -- Previous powers
> >             top =3D repeat(r + COMPL, r)
> >             verify (n, n + 1)
> >             i =3D n
> >             while i > 1 do
> >                 while top[i] > 1 do
> >                     top[i] -=3D 1
> >                     k =3D top[i]
> >                     while i < n do
> >                         i +=3D 1
> >                         top[i] =3D k  -- Avoid repeating previous tes=
ts
> >                     end while
> >                     verify(n, n + 1)
> >                 end while
> >                 i -=3D 1
> >             end while
> >         end for
> >         for n =3D 2 to r do -- Present power
> >             top =3D repeat(r + COMPL, r)
> >             verify (n, p)
> >             i =3D n
> >             while i do
> >                 while top[i] > 1 do
> >                     top[i] -=3D 1
> >                     k =3D top[i]
> >                     while i < n do
> >                         i +=3D 1
> >                         top[i] =3D k  -- Avoid repeating previous tes=
ts
> >                     end while
> >                     verify(n, p)
> >                 end while
> >                 i -=3D 1
> >             end while
> >         end for
> >     end while
> > end procedure
> >
> > fermat()
> >
> >



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<HTML><BODY STYLE=3D"font:10pt verdana; border:none;"><DIV>&nbsp;</DIV> <=
DIV>actually, there is a rather large book that details the&nbsp;proof ( =
that is, details of the steps taken to solve the problem ) of fermats the=
orem that was written (I believe) in the nineties--I've never read the wo=
rk myself, but I seen it referenced quite a few times.&nbsp; If I can, I'=
ll try to find the title.</DIV> <DIV>&nbsp;</DIV> <DIV>~Nathan</DIV> <BLO=
CKQUOTE style=3D"PADDING-RIGHT: 0px; PADDING-LEFT: 5px; MARGIN-LEFT: 5px;=
 BORDER-LEFT: #000000 2px solid; MARGIN-RIGHT: 0px"> <DIV style=3D"FONT: =
10pt Arial">----- Original Message -----</DIV> <DIV style=3D"BACKGROUND: =
#e4e4e4; FONT: 10pt Arial; COLOR: black"><B>From:</B> rforno at tutopia.com<=
/DIV> <DIV style=3D"FONT: 10pt Arial"><B>Sent:</B> Thursday, August 15, 2=
002 12:44 AM</DIV> <DIV style=3D"FONT: 10pt Arial"><B>To:</B> EUforum</DI=
V> <DIV style=3D"FONT: 10pt Arial"><B>Subject:</B> RE: Fermat extended - =
Only for mathemathicians</DIV> <DIV>&nbsp;</DIV>=3D=3D=3D=3D=3D=3D=3D=3D=3D=
=3D=3D=3D The Euphoria Mailing List =3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D =
<BR><BR>Apparently you did not read the caption at the top of the program=
, or my<BR>English is very bad.<BR>I know that this program cannot prove =
the conjecture to be true, but it can<BR>prove it to be false.<BR>Moreove=
r, I was interested in knowing if someone posed the same conjecture<BR>th=
at I call "extended Fermat theorem".<BR>About the original conjecture, I =
remember having heard that someone finally<BR>proved it to be true, not b=
y means of a computer program but using advanced<BR>math theory.<BR>-----=
 Original Message -----<BR>From: &lt;rswiston at hotmail.com&gt;<BR>To: EUfo=
rum &lt;EUforum at topica.com&gt;<BR>Sent: Thursday, August 15, 2002 1:23 AM=
<BR>Subject: Re: Fermat extended - Only for mathemathicians<BR><BR><BR>&g=
t;<BR>&gt; I think your information is incorrect.&nbsp; Femat's theorem i=
s only true since<BR>&gt; no one can find a value of p to make it false.&=
nbsp; (Remember theorem means a<BR>&gt; statement yet to be proven false)=
.&nbsp; To prove the theorem, one must provide<BR>&gt; proof that the "co=
njecture" is true for all values of p (not simply a few<BR>&gt; selected =
ones... and infinity is a pretty big number!).&nbsp; Since this is<BR>&gt=
; nearly inpossible (I say nearly since super computers can do marvelous<=
BR>&gt; things these days) no one has yet to prove (or disprove) the theo=
rem.<BR>Your<BR>&gt; program can produce sums given a provided input from=
 the variables, but<BR>will<BR>&gt; still not "prove" the theorem.&nbsp; =
It is simply looking for a value that will<BR>&gt; prove the theorem fals=
e (which may well happen if allowed to run long<BR>&gt; enough... in a lo=
op that doesn't end until the proof has been found<BR>invalid)<BR>&gt; an=
d therefore does not prove the theorem.&nbsp; (AUUGHH high school geometr=
y<BR>&gt; rears its ugly head!).&nbsp; Unfortunately, computer programs a=
re designed<BR>around<BR>&gt; numbers either set or inputed from a loop o=
r user input.&nbsp; They are not<BR>&gt; designed to act upon an unknown =
(do not confuse the term variable we<BR>&gt; mathmeticians use with the s=
ame term computer programmers use).<BR>&gt;<BR>&gt; -Robert<BR>&gt;<BR>&g=
t; ----- Original Message -----<BR>&gt; From: &lt;rforno at tutopia.com&gt;<=
BR>&gt; To: "EUforum" &lt;EUforum at topica.com&gt;<BR>&gt; Sent: Tuesday, A=
ugust 13, 2002 10:08 PM<BR>&gt; Subject: Fermat extended - Only for mathe=
mathicians<BR>&gt;<BR>&gt;<BR>&gt; &gt; Dear EUphorians:<BR>&gt; &gt; App=
arently, someone proved the last theorem by Fermat to be true.<BR>&gt; &g=
t; I don't know if the following extension to Fermat's theorem (or<BR>&gt=
; conjecture)<BR>&gt; &gt; has ever be posed by someone, but here it is, =
with a program that tries<BR>to<BR>&gt; &gt; find a counterexample. I've =
found no one yet.<BR>&gt; &gt; Comments are welcome.<BR>&gt; &gt;<BR>&gt;=
 &gt; -- Trying to find a counterexample for the "extended-Fermat conject=
ure",<BR>&gt; &gt; that<BR>&gt; &gt; -- x[1]^p+x[2]^p...+x[n]^p =3D z^p, =
for x[i] &gt; 0, 1 &lt; n &lt; p has no integer<BR>&gt; &gt; -- solutions=
.<BR>&gt; &gt; -- Author R. M. Forno - Version 1.0 - 2002/08/13<BR>&gt; &=
gt;<BR>&gt; &gt; constant COMPL =3D 30 -- Start with numbers somewhat big=
<BR>&gt; &gt; sequence top -- The elements<BR>&gt; &gt;<BR>&gt; &gt; proc=
edure verify(integer n, integer p) -- Verify conjecture<BR>&gt; &gt;&nbsp=
;&nbsp;&nbsp;&nbsp; atom root, sum<BR>&gt; &gt;&nbsp;&nbsp;&nbsp;&nbsp; i=
nteger r<BR>&gt; &gt;&nbsp;&nbsp;&nbsp;&nbsp; sum =3D 0<BR>&gt; &gt;&nbsp=
;&nbsp;&nbsp;&nbsp; for i =3D 1 to n do -- Always perform the sum to avoi=
d rounding errors<BR>&gt; &gt;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&=
nbsp; sum +=3D power(top[i], p)<BR>&gt; &gt;&nbsp;&nbsp;&nbsp;&nbsp; end =
for<BR>&gt; &gt;&nbsp;&nbsp;&nbsp;&nbsp; root =3D power(sum, 1 / p)<BR>&g=
t; &gt;&nbsp;&nbsp;&nbsp;&nbsp; r =3D floor(root + 0.5) -- Beware of roun=
ding errors<BR>&gt; &gt;&nbsp;&nbsp;&nbsp;&nbsp; if power(r, p) =3D sum t=
hen -- Show results... some day<BR>&gt; &gt;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp=
;&nbsp;&nbsp;&nbsp; printf(1, "Power: %d Left: %f Right:", {p, root})<BR>=
&gt; &gt;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; for i =3D 1 to =
n do<BR>&gt; &gt;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&n=
bsp;&nbsp;&nbsp; printf(1, " %d", top[i])<BR>&gt; &gt;&nbsp;&nbsp;&nbsp;&=
nbsp;&nbsp;&nbsp;&nbsp;&nbsp; end for<BR>&gt; &gt;&nbsp;&nbsp;&nbsp;&nbsp=
;&nbsp;&nbsp;&nbsp;&nbsp; puts(1, '\n')<BR>&gt; &gt;&nbsp;&nbsp;&nbsp;&nb=
sp; end if<BR>&gt; &gt; end procedure<BR>&gt; &gt;<BR>&gt; &gt; procedure=
 fermat()<BR>&gt; &gt;&nbsp;&nbsp;&nbsp;&nbsp; integer p, k, i, r<BR>&gt;=
 &gt;&nbsp;&nbsp;&nbsp;&nbsp; p =3D 2<BR>&gt; &gt;&nbsp;&nbsp;&nbsp;&nbsp=
; while p &lt;=3D 20 do<BR>&gt; &gt;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&=
nbsp;&nbsp; p +=3D 1<BR>&gt; &gt;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbs=
p;&nbsp; printf(1, "Testing exponent %d\n", p)<BR>&gt; &gt;&nbsp;&nbsp;&n=
bsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; r =3D p - 1<BR>&gt; &gt;&nbsp;&nbsp;&n=
bsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; for n =3D 2 to r - 1 do&nbsp; -- Previ=
ous powers<BR>&gt; &gt;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&n=
bsp;&nbsp;&nbsp;&nbsp; top =3D repeat(r + COMPL, r)<BR>&gt; &gt;&nbsp;&nb=
sp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; verify (n=
, n + 1)<BR>&gt; &gt;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbs=
p;&nbsp;&nbsp;&nbsp; i =3D n<BR>&gt; &gt;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&n=
bsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; while i &gt; 1 do<BR>&gt; &gt;&n=
bsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nb=
sp;&nbsp;&nbsp;&nbsp; while top[i] &gt; 1 do<BR>&gt; &gt;&nbsp;&nbsp;&nbs=
p;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp=
;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; top[i] -=3D 1<BR>&gt; &gt;&nbsp;&nbsp;&nb=
sp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbs=
p;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; k =3D top[i]<BR>&gt; &gt;&nbsp;&nbsp;&nb=
sp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbs=
p;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; while i &lt; n do<BR>&gt; &gt;&nbsp;&nbs=
p;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp=
;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; i +=3D 1<BR=
>&gt; &gt;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nb=
sp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbs=
p;&nbsp; top[i] =3D k&nbsp; -- Avoid repeating previous tests<BR>&gt; &gt=
;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;=
&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; end while<BR>&gt; &gt;&n=
bsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nb=
sp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; verify(n, n + 1)<BR>&gt; &g=
t;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp=
;&nbsp;&nbsp;&nbsp;&nbsp; end while<BR>&gt; &gt;&nbsp;&nbsp;&nbsp;&nbsp;&=
nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; i=
 -=3D 1<BR>&gt; &gt;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp=
;&nbsp;&nbsp;&nbsp; end while<BR>&gt; &gt;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&=
nbsp;&nbsp;&nbsp; end for<BR>&gt; &gt;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp=
;&nbsp;&nbsp; for n =3D 2 to r do -- Present power<BR>&gt; &gt;&nbsp;&nbs=
p;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; top =3D re=
peat(r + COMPL, r)<BR>&gt; &gt;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;=
&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; verify (n, p)<BR>&gt; &gt;&nbsp;&nbsp;&nbs=
p;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; i =3D n<BR>&gt; =
&gt;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nb=
sp; while i do<BR>&gt; &gt;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbs=
p;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; while top[i] &gt; 1 do=
<BR>&gt; &gt;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;=
&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; top[i] -=3D =
1<BR>&gt; &gt;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp=
;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; k =3D top[i=
]<BR>&gt; &gt;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp=
;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; while i &lt=
; n do<BR>&gt; &gt;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;=
&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&=
nbsp;&nbsp;&nbsp; i +=3D 1<BR>&gt; &gt;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbs=
p;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp=
;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; top[i] =3D k&nbsp; -- Avoid repeati=
ng previous tests<BR>&gt; &gt;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&=
nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&n=
bsp; end while<BR>&gt; &gt;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbs=
p;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp=
; verify(n, p)<BR>&gt; &gt;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbs=
p;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; end while<BR>&gt; &gt;=
&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&=
nbsp;&nbsp;&nbsp;&nbsp; i -=3D 1<BR>&gt; &gt;&nbsp;&nbsp;&nbsp;&nbsp;&nbs=
p;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; end while<BR>&gt; &gt;&nbsp;=
&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; end for<BR>&gt; &gt;&nbsp;&nbs=
p;&nbsp;&nbsp; end while<BR>&gt; &gt; end procedure<BR>&gt; &gt;<BR>&gt; =
&gt; fermat()<BR>&gt; &gt;<BR>&gt; &gt;<BR>&gt;<BR>&gt;<BR>&gt;<BR><BR>=3D=
=3D^=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=
=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=
=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D<BR>This email was sent t=
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