OpenEuphoria

Re: error?

• Posted by Don Phillips <EuNexus at yahoo.com> Oct 24, 2002
• 468 views

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Actuall no, in Euphoria this is a perfectly valid statement.  The docs are a wee
bit hard to understand on this point, but it works out like this:
slice[ # .. (anything greater than #) ] = a sequence
slice[ # .. # ] = a sequence length 1

slice[ # .. #-1 ] = a sequence length 0

slice[ # .. (anything less than #-1) ] = error


Ok, if 
decimalcount = 1
(the debug screen says it is 1)
then shouldn't this line crash?:

resultnum = resultnum[1..decimalcount-1] & "." & 
resultnum[decimalcount..length(resultnum)]

since it is the same as:
resultnum[1..0] 
?

Kat






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<P>Actuall no, in Euphoria this is a perfectly valid statement.&nbsp; The docs
are a wee bit hard to understand on this point, but it works out like this:
<P>slice[ # .. (anything greater than #) ] = a sequence
<P>slice[ # ..&nbsp;# ] = a sequence length 1</P>
<P>slice[ # ..&nbsp;#-1 ] = a sequence length 0</P>
<P>slice[ # ..&nbsp;(anything less than #-1)&nbsp;] = error</P>
<P>&nbsp;<B><I>Kat &lt;kat at kogeijin.com&gt;</I></B> wrote:
<BLOCKQUOTE style="PADDING-LEFT: 5px; MARGIN-LEFT: 5px; BORDER-LEFT: #1010ff 2px
solid">============ The Euphoria Mailing List ============ <BR><BR>Ok, if
<BR>decimalcount = 1<BR>(the debug screen says it is 1)<BR>then shouldn't this
line crash?:<BR><BR>resultnum = resultnum[1..decimalcount-1] &amp; "." &amp;
<BR>resultnum[decimalcount..length(resultnum)]<BR><BR>since it is the same
as:<BR>resultnum[1..0]
<BR>?<BR><BR>Kat<BR><BR>==^================================================================<BR>This
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