Re: Timeing Question
- Posted by Euman <euman at bellsouth.net> Feb 08, 2001
- 463 views
> There are 65,536 ticks in one hour until you use tick_rate(100), then you > have 360,000 ticks in one hour. > > I tried this: > > include machine.e > atom t > > t = time() > while time() = t do -- wait next tick > end while > ? 1/(time()-t) > > tick_rate(100) > > t = time() > while time() = t do > end while > ? 1/(time()-t) > > For some reason I don't ever get 18.2 ticks per second in the first > instance; I get either 16.66 or 20. In the second instance I always get a > result close to 100. > > - Colin Taylor > > Euman wrote: > > If There are 64K (65,536) ticks in one hour > > Why is it I cant seem to get this to work > 18.204 ticks per second > > > This would explain the difference in timeing of loops (profiling) If you run a program to test for speed occasionally the times are different for the same algorytm. Maybe Robert hasnt been told about this either. or maybe he knows but hasnt done anything to correct it. Robert? Euman