Re: Find what?
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----- Original Message -----=20
From: Derek Parnell=20
To: EUPHORIA at LISTSERV.MUOHIO.EDU=20
Sent: Monday, November 06, 2000 3:51 PM
Subject: Re: Find what?
OOOOPS! That won't work. That's what you get from trying to code while =
eating breakfast at the same time.
Try this instead...
=20
sequence result, word
integer x
result =3D {}
word =3D "experience"
for i =3D 1 to length(word) do
if word[i] =3D 'e' then
result &=3D i
end if
end for
? result -- Should display {1,4,7,10}
------
Derek Parnell
Melbourne, Australia
(Vote [1] The Cheshire Cat for Internet Mascot)
----- Original Message -----=20
From: Derek Parnell=20
To: EUPHORIA at LISTSERV.MUOHIO.EDU=20
Sent: Tuesday, November 07, 2000 10:45 AM
Subject: Re: Find what?
Hi Thomas,
no it doesn't return a sequence.
=20
From the manual:-
=20
find
Syntax: i =3D find(x, s) =20
Description: Find x as an element of s. If successful, return =
the index of the first element of s that matches. If unsuccessful return =
0. =20
=20
Note the key phrase in the manual "index of the first element".
To find all occurrences try this...
sequence result, word
integer x
result =3D {}
word =3D "experience"
for i =3D 1 to length(word) do
x =3D find('e', word)
if x then
result &=3D x
end if
end for
? result -- Should display {1,4,7,10}
------
Derek Parnell
Melbourne, Australia
(Vote [1] The Cheshire Cat for Internet Mascot)
----- Original Message -----=20
From: Paul Kerslake=20
To: EUPHORIA at LISTSERV.MUOHIO.EDU=20
Sent: Tuesday, November 07, 2000 10:29 AM
Subject: Find what?
Hi evr'yone
=20
I was wondering about find(). What if there are 2 of the same =
characters in a sequence? Like this:
=20
sequence word
word=3D"beet"
atom findit
=20
findit=3Dfind("e", word)
? findit
=20
Does it give a [2..3] back?
=20
-->Thanks
--->Thomas
-------/\=3D=3D=3D=3D
Sorry, I meant to add another "bit" to it. I forgot to include =
that the users input was used in find(). So it would be something like:
include get.e
integer input
sequence word
word=3D"beef"
atom findit
input=3Dgets(0)
findit=3Dfind(input[1], word) --input[1] otherwise the [#,10] =
extra 10 for enter is added
? findit
=20
--->Thanks
------> Thomas
-------/\=3D=3D=3D=3D=3D
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<DIV=20
style=3D"BACKGROUND: #e4e4e4; FONT: 10pt arial; font-color: =
black"><B>From:</B>=20
<A href=3D"mailto:dparnell at BIGPOND.NET.AU" =
title=3Ddparnell at BIGPOND.NET.AU>Derek=20
Parnell</A> </DIV>
<DIV style=3D"FONT: 10pt arial"><B>To:</B> <A=20
href=3D"mailto:EUPHORIA at LISTSERV.MUOHIO.EDU"=20
title=3DEUPHORIA at LISTSERV.MUOHIO.EDU>EUPHORIA at LISTSERV.MUOHIO.EDU</A> =
</DIV>
<DIV style=3D"FONT: 10pt arial"><B>Sent:</B> Monday, November 06, 2000 =
3:51=20
PM</DIV>
<DIV style=3D"FONT: 10pt arial"><B>Subject:</B> Re: Find what?</DIV>
<DIV><BR></DIV>
<DIV><FONT face=3DArial size=3D2>OOOOPS! That won't work. That's what =
you get from=20
trying to code while eating breakfast at the same time.</FONT></DIV>
<DIV><FONT face=3DArial size=3D2>Try this instead...</FONT></DIV>
<DIV><FONT face=3DArial size=3D2></FONT> </DIV>
<DIV>
<P><FONT size=3D2>sequence result, word<BR>integer x<BR></FONT><FONT=20
size=3D2>result =3D {}<BR>word =3D "experience"</FONT><FONT =
size=3D2><BR>for i =3D 1 to=20
length(word) do<BR> if word[i] =3D=20
'e' then<BR> result =
&=3D i<BR> end=20
if<BR>end for<BR>? result -- Should display =
{1,4,7,10}</FONT></P></DIV>
<DIV>------<BR>Derek Parnell<BR>Melbourne, Australia<BR>(Vote [1] The =
Cheshire=20
Cat for Internet Mascot)<BR></DIV>
<BLOCKQUOTE dir=3Dltr=20
style=3D"BORDER-LEFT: #000000 2px solid; MARGIN-LEFT: 5px; =
MARGIN-RIGHT: 0px; PADDING-LEFT: 5px; PADDING-RIGHT: 0px">
<DIV style=3D"FONT: 10pt arial">----- Original Message ----- </DIV>
<DIV=20
style=3D"BACKGROUND: #e4e4e4; FONT: 10pt arial; font-color: =
black"><B>From:</B>=20
<A href=3D"mailto:dparnell at BIGPOND.NET.AU" =
title=3Ddparnell at BIGPOND.NET.AU>Derek=20
Parnell</A> </DIV>
<DIV style=3D"FONT: 10pt arial"><B>To:</B> <A=20
href=3D"mailto:EUPHORIA at LISTSERV.MUOHIO.EDU"=20
=
title=3DEUPHORIA at LISTSERV.MUOHIO.EDU>EUPHORIA at LISTSERV.MUOHIO.EDU</A> =
</DIV>
<DIV style=3D"FONT: 10pt arial"><B>Sent:</B> Tuesday, November 07, =
2000 10:45=20
AM</DIV>
<DIV style=3D"FONT: 10pt arial"><B>Subject:</B> Re: Find what?</DIV>
<DIV><FONT face=3DArial size=3D2></FONT><FONT face=3DArial=20
size=3D2></FONT><BR></DIV>
<DIV><FONT face=3DArial size=3D2>Hi Thomas,</FONT></DIV>
<DIV><FONT face=3DArial size=3D2>no it doesn't return a =
sequence.</FONT></DIV>
<DIV><FONT face=3DArial size=3D2></FONT> </DIV>
<DIV><FONT face=3DArial size=3D2>From the manual:-</FONT></DIV>
<DIV><FONT face=3DArial size=3D2></FONT> </DIV>
<DIV>
<CENTER><B>find</B></CENTER>
<P>
<TABLE border=3D0 cellPadding=3D2 cellSpacing=3D2>
<TBODY>
<TR>
<TD vAlign=3Dtop><B>Syntax:</B></TD>
<TD><FONT face=3D"Arial, Helvetica">i =3D find(x, s) =
</FONT></TD></TR>
<TR>
<TD vAlign=3Dtop><B>Description:</B></TD>
<TD>Find x as an element of s. If successful, return the index =
of the=20
first element of s that matches. If unsuccessful return 0.=20
</TD></TR></TBODY></TABLE></P>
<P><FONT face=3DArial size=3D2></FONT> </P>
<P><FONT face=3DArial size=3D2>Note the key phrase in the manual =
"index of the=20
<STRONG>first</STRONG> element".</FONT></P>
<P><FONT face=3DArial size=3D2>To find all occurrences try =
this...</FONT></P>
<P><FONT size=3D2>sequence result, word<BR>integer x<BR></FONT><FONT =
size=3D2>result =3D {}<BR>word =3D "experience"</FONT><FONT =
size=3D2><BR>for i =3D 1=20
to length(word) do<BR> x =3D find('e', word)<BR> if x=20
then<BR> result &=3D x<BR> end =
if<BR>end=20
for<BR>? result -- Should display {1,4,7,10}</FONT></P></DIV>
<DIV>------<BR>Derek Parnell<BR>Melbourne, Australia<BR>(Vote [1] =
The=20
Cheshire Cat for Internet Mascot)<BR></DIV>
<BLOCKQUOTE dir=3Dltr=20
style=3D"BORDER-LEFT: #000000 2px solid; MARGIN-LEFT: 5px; =
MARGIN-RIGHT: 0px; PADDING-LEFT: 5px; PADDING-RIGHT: 0px">
<DIV style=3D"FONT: 10pt arial">----- Original Message ----- =
</DIV>
<DIV=20
style=3D"BACKGROUND: #e4e4e4; FONT: 10pt arial; font-color: =
black"><B>From:</B>=20
<A href=3D"mailto:paulk at UNISERVE.COM" =
title=3Dpaulk at UNISERVE.COM>Paul=20
Kerslake</A> </DIV>
<DIV style=3D"FONT: 10pt arial"><B>To:</B> <A=20
href=3D"mailto:EUPHORIA at LISTSERV.MUOHIO.EDU"=20
=
title=3DEUPHORIA at LISTSERV.MUOHIO.EDU>EUPHORIA at LISTSERV.MUOHIO.EDU</A> =
</DIV>
<DIV style=3D"FONT: 10pt arial"><B>Sent:</B> Tuesday, November 07, =
2000=20
10:29 AM</DIV>
<DIV style=3D"FONT: 10pt arial"><B>Subject:</B> Find what?</DIV>
<DIV><FONT face=3DArial size=3D2></FONT><FONT face=3DArial=20
size=3D2></FONT><BR></DIV>
<DIV><FONT face=3DArial size=3D2>Hi evr'yone</FONT></DIV>
<DIV><FONT face=3DArial size=3D2></FONT> </DIV>
<DIV><FONT face=3DArial size=3D2>I was wondering about find(). =
What if there=20
are 2 of the same characters in a sequence? Like =
this:</FONT></DIV>
<DIV><FONT face=3DArial size=3D2></FONT> </DIV>
<DIV><FONT face=3DArial size=3D2>sequence word</FONT></DIV>
<DIV><FONT face=3DArial size=3D2>word=3D"beet"</FONT></DIV>
<DIV><FONT face=3DArial size=3D2>atom findit</FONT></DIV>
<DIV><FONT face=3DArial size=3D2></FONT> </DIV>
<DIV><FONT face=3DArial size=3D2>findit=3Dfind("e", =
word)</FONT></DIV>
<DIV><FONT face=3DArial size=3D2>? findit</FONT></DIV>
<DIV><FONT face=3DArial size=3D2></FONT> </DIV>
<DIV><FONT face=3DArial size=3D2>Does it give a [2..3] =
back?</FONT></DIV>
<DIV><FONT face=3DArial size=3D2></FONT> </DIV>
<DIV><FONT face=3DArial size=3D2>-->Thanks</FONT></DIV>
<DIV><FONT face=3DArial size=3D2>--->Thomas</FONT></DIV>
<DIV><FONT face=3DArial =
size=3D2>-------/\=3D=3D=3D=3D</FONT></DIV>
<DIV> </DIV>
<DIV><FONT face=3DArial size=3D2>Sorry, I meant to add another =
"bit" to it. I=20
forgot to include that the users input was used in find(). So it =
would be=20
something like:</FONT></DIV>
<DIV> </DIV>
<DIV><FONT face=3DArial size=3D2>include get.e</FONT></DIV>
<DIV> </DIV>
<DIV><FONT face=3DArial size=3D2>integer input</FONT></DIV>
<DIV><FONT face=3DArial size=3D2>
<DIV><FONT face=3DArial size=3D2>sequence word</FONT></DIV>
<DIV><FONT face=3DArial size=3D2>word=3D"beef"</FONT></DIV>
<DIV><FONT face=3DArial size=3D2>atom findit</FONT></DIV>
<DIV><FONT face=3DArial =
size=3D2></FONT> input=3Dgets(0)</DIV>
<DIV><FONT face=3DArial size=3D2>findit=3Dfind(input[1], =
word) =20
--input[1] otherwise the [#,10] extra 10 for enter is =
added</FONT></DIV>
<DIV><FONT face=3DArial size=3D2>? findit</FONT></DIV>
<DIV><FONT face=3DArial size=3D2></FONT> </DIV>
<DIV> </DIV>
<DIV>--->Thanks</DIV>
<DIV>------> Thomas</DIV>
<DIV> </DIV>
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