Re: Find 3: The Reckoning
- Posted by Kat <gertie at PELL.NET> Oct 31, 2000
- 465 views
Then why did you send it back for the rest of us to download again??? On 31 Oct 2000, at 23:02, Euman wrote: > I dont like it!!!! > > PLEASE dont make us download extra bytes > to play sounds...... > > Thanks: > euman at bellsouth.net > > ----- Original Message ----- > From: Liona Kerslake > To: EUPHORIA at LISTSERV.MUOHIO.EDU > Sent: Tuesday, October 31, 2000 6:49 PM > Subject: Re: Find 3: The Reckoning > > > > ----- Original Message ----- > From: Derek Parnell > To: EUPHORIA at LISTSERV.MUOHIO.EDU > Sent: Sunday, October 29, 2000 10:42 AM > Subject: Re: Find 3: The Reckoning > > > Ok Thomas, I'll bite. > > ------ > Derek Parnell > Melbourne, Australia > (Vote [1] The Cheshire Cat for Internet Mascot) > > > include get.e > sequence names,curname > object input > integer location > atom wn > wn=rand(3) > names ={"bob","them","worms"} > curname=names[wn] > printf(1,"curname: %s\n",{curname}) > > input=gets(0) > ? curname > puts(1,"\n") > ? input > location = find(input[1],names[2]) > This previous line is saying "Find where the first character of input > inside of the second sequence of names". Is this what you are really > trying to find out? I suspect you are trying to find out if "input" is one > of the three possible names. If that is so, try this instead... > if sequence(input) then > -- Strip off the trailing newline char. > input = input[1 .. length(input) - 1] > -- convert to lowercase. > input = lower(input) > -- See if the input sequence is one of the sequences in names. > location = find(input, names) > -- "location" should equal 0, 1, 2, or 3 now. > else > -- End-Of-File (Ctrl-Z) entered. > location = 0 > end if > > > puts(1,"\n") > ? location > > > The "location" variable only gives a correct number if "them" is > used. > And what is the correct number? What were you expecting to see? > Nothing else. I've looked at all the documentation I've got and either I > am quite blind or, I just haven't found my solution. Anywho, if you > could solve this problem, I'd be most grateful.... > > I suspect you are confused by the find() function. It takes two > parameters, the first can be an atom or a sequence but the second must be > a sequence. It then scans each element in the second parameter to see if > it equals the first parameter. If so, it returns the number of the element > in the second parmeter that equalled the first parameter. > > This means that if the first parameter is a sequence, as is your case > here, then each of the elements in the second parmeter should be sequences > too. Also, this is what you have coded for names. However, in your coding > of find() you used input[1] which is not a sequence but the first > character of input. It is a single character - an atom. Also, you coded > the second parameter as names[2] which is a sequence if characters - > namely "them" . Thus, find() went looking through the characters ''t', > 'h', 'e', and 'm' to see if the first character of input equalled any. > > This would mean that location would be non-zero, 1 to 4, for any input > that begun with 't', 'h', 'e', or 'm'. > > Das Svendanya > Thomas > > > PS. This should be the last one......... > Yeah, sure Thomas. --------I meant the last one on this program, but, > you're right > > What I'm trying to do here is get the placement of an individual letter > from a word. So if the word is "moor" and the user types in 'o'.....wait, > bad example, there are two o's....would eusphoria see that as [2..3]? > > okay, if the user types in 'r', whatever variable I assigned find() to > will be 4. > > -Hope this clarifies things..... > -HAPPY HALLOWEEN!!! > -Thomas > > PS. How'd you like the Halloween-esque sound? > >