OpenEuphoria

Re: Little bit of PHYSICS

• Posted by The Johnson Family <thedjs at INAME.COM> Jan 30, 2000
• 535 views

Easy - every second, the object will move horizontally x metres/second
(where x is it's initial horizontal speed)
Every second it will also move vertically y-g metres, where y is the
vertical speed it started off at. Easier to explain in equations:

At time t:
horizontal position = previous horizontal position + initial horizontal
velocity
vertical position = previous vertical position + (previous vertical
velocity - 9.8)

Weight does not matter, air resistance is usually negligable
Hope this helps, sorry I couldnt be stuffed extrapolating the equations for
position at time.

Nick

----- Original Message -----
From: David Roach <roachd_76 at YAHOO.COM>
To: <EUPHORIA at LISTSERV.MUOHIO.EDU>
Sent: Sunday, January 30, 2000 11:56 AM
Subject: Little bit of PHYSICS


> Hello ALL,
> Here's a good one for you. I need to find some physics stuff, equations
> mostly. I need to find out if an object is propeled at this speed and
> at this angle and weighs this much. Where will it be at a point on a
> graph at this distance. So pretty much your basic phisics stuff that
> I can't remember or find on the net. If anyone could help me with this
> I would really apreciate it. Just working on my next program. Any
equations
> or places on the net to find this physics stuff would be great.
>
>