Re: 32-bit random numbers
Hi igor,
"K * (rand(N) - 1) + rand(K) - 1"
It looks flat, but what is your intended advantage over
N*(rand(N)-1)+rand(N)-1, {N=#1000}
??
Notice you can also extend that one:
N*(rand(N)-1)+rand(N)-1
goes to:
N*N*(rand(N)-1)+N*(rand(N)-1)+rand(N)-1
if N is an integer multiple of the number of terms minus 1,
or:
N*N*(rand(N2)-1)+N*(rand(N2)-1)+rand(N2)-1
if N2=number of terms minus 1 .
This gives the ability to get higher and higher random numbers
Take care,
Al
And, good luck with your Euphoria programming!
My bumper sticker: "I brake for LED's"
|
Not Categorized, Please Help
|
|