Re: Fast appending and sorting of alot of short strings

new topic     » goto parent     » topic index » view thread      » older message » newer message

On Fri, 8 Oct 2004 22:56:04 -0500, Kat <gertie at visionsix.com> wrote:

>>  table[current+1..tabused]=table[current..tabused-1]
>
>But you are dropping the last tabused element of table, aren't you?
Perhaps. I should have coded tabused+=1 immediately before the above
statement, to make it clearer. It also depends on how you calculate
"current", eg inserting 4 into {1,3,5,7}, is current 2 or 3? If a
binary search fails, I'm not sure which it would return. Perhaps it
would be wise to test and add 1 just in case. To be honest, I've only
used this technique to remove chunks of a table, and usually shifting
relatively small blocks about near the end of the table, which may
have exaggerated the benefits I experienced (vs. "&").
> Or is it spare space preappended to table?
Yes, the intention is that table[tabused+1..length(tabused)] is
unused, and that before the above if tabused=length(tabused) you
append additional spare space.

Regards,
Pete

new topic     » goto parent     » topic index » view thread      » older message » newer message

Search



Quick Links

User menu

Not signed in.

Misc Menu