OpenEuphoria

Re: reading strings

• Posted by Pete Lomax <petelomax at blueyonder.co.uk> Sep 06, 2006
• 553 views

On Tue, 05 Sep 2006 19:45:02 -0700, Hayden McKay
<guest at RapidEuphoria.com> wrote:

>nb. After reading your post and doing some testing I found that my routine will
>crash if 'atom lp' points to a 0.
<snip>
>but I should change routine to accomodate as follows.
>}}}
<eucode>
>--  if loc then
>    if loc >= 1 then
>        chunk = chunk[1..(loc-1)]
>    else
>        chunk = {}   -- return empty string.
>    end if
></eucode>
{{{

This rang a few alarm bells. First question is what error message did
you get, exactly, that this is supposed to fix? I expect it was an
error in the peek, if lp was zero or pointed to a zero in memory which
was not followed by 255 bytes of readable memory. The change might
solve an error "slice end is xxx ", but I doubt you got that. What you
might have done is by adding those 4 lines of code made sure that a
zero was now followed by at least 255 bytes of readable memory (code).

Note that chunk = chunk[1..0] is a valid Eu statement.

If anything, I'd say that as it stands if you peek a 256-character
string, with no terminator in it anywhere, it will return {}, or would
have crashed before.

Regards,
Pete