OpenEuphoria

Re: operation with sequences

• Posted by rubis at fem.unicamp.br Sep 05, 2002
• 447 views

I think all my problem come for this:

sequence a
atom b
atom c
sequence d
sequence e
a=3D{}
b=3D1
c=3D1
d=3D{1}
e=3D{1}

After some "exercises", I could now understand that :

a=3Db&c gives a=3D{1,1}  and a=3Dd&e  gives also a=3D{1,1}  The same !

But the problem was that I was expecting a=3D{{1},{1}} !!!!

So I "discover" :>)   that to obtain a=3D{{1},{1}} I have to do this:

a=3D{d}&{e}  .

My problem is solved.

This routine from Derek:

-- Convert the integers into strings and concatenate them.
  c =3D sprintf("%d%d",{a,b})
  -- Convert the resultant string into an atom.
  c =3D value(c)
  -- Ditch the success flag and convert the atom into a sequence.
  c =3D {c[2]}

is usefull for what I was trying to do, but now I change the way of solve=20
the problem, after understanding better the sequences.

I=B4d like to thank you all for your help.


Obrigado !

Rubens M. Luciano
icq number 1556563
Campinas
Brazil

At 01:32 29/8/2002, you wrote:
>
>29/08/2002 11:06:13 AM, rubis at fem.unicamp.br wrote:
>
> >
> >Simple question:
> >
> >It's possible to do this ?
> >
> >atom a
> >atom b
> >sequence c
> >a=3D1
> >b=3D1
> >
> >c=3D{11}
> >
> >Trying "&" or "append" I obtain only c=3D{1,1}
>
>Hi Rubens,
>In Euphoria, an atom holds a single number, and a sequence holds a single=
=20
>list of objects. An object
>can hold either a single atom or a single sequence.
>Your example is a bit ambiguous. It looks like you are trying to join=20
>together two numbers.
>
>Are these right...
>a =3D 1
>b =3D 1
>=3D=3D> c =3D {11}
>
>a =3D 12
>b =3D 3
>=3D=3D> c =3D {123}
>
>a =3D 3
>b =3D 21
>=3D=3D> c =3D {321}
>
>It might be easier to help you if you explain a bit more about what you=20
>are trying to achieve. For
>example, where do the values of 'a' and 'b' come from? What are you=20
>intending to do with 'c'?
>
>As it stands, with the information you have given us, the way I could=20
>suggest is to do this...
>
>  -- Convert the integers into strings and concatenate them.
>  c =3D sprintf("%d%d",{a,b})
>  -- Convert the resultant string into an atom.
>  c =3D value(c)
>  -- Ditch the success flag and convert the atom into a sequence.
>  c =3D {c[2]}
>
>
>Hope this helps.
>-----------------
>Derek.
>
>
>