OpenEuphoria

Re: Rather large number

• Posted by Hawke <mdeland at NWINFO.NET> Nov 24, 1998
• 525 views

> Molasses wrote:
> Could anyone please help me in a large calculation?
> Let me specify 'large':
> (480000^16777216) / 756864000
> That's 480000 to the power of 16777216, divided by 756864000.

> What's it for?
> It's the number of years it would take to watch a screen 800x600 24bit
> color go through every possible combination at 24 frames per second.


ummmm, to do what you are saying, you can move
*much* faster than 24fps... *MUCH* faster...
since you are basically only changing one pixel
at any given moment.... you can simply walk around
the screen using whatever pixel() command there is in
that library... and, you can set, likely, several hundred
pixels in a second... depending on the machine, easily
thousands per second...
in fact....
you're setting 480000*24 pixels/sec
which is 11520000...

so, instead of multiplying 24*60*60*24*365 to get the
divisor, you *should* be multiplying 11520000*60*60*24*365
ie: 60*60*24*365=sec/year = 31536000
you multiplied 24fps*31536000sec/year = 756864000

you should have done 11520000pix/sec*31536000sec/year
= 3.6329472e14 for your divisor...

this way, you can see your units matching and
crossing out...
pix/sec * sec/year = pix/year
you needed to have pix/year on the right side
of the equation because you had pix on the left
and were trying to solve for year...
once you bring over the divisor, you have
pix/pix = year which is what you're after...

ie:

480000^16.7M pix  / 3.63e14 pix/year = ? year

remembering that division is inverse multiplication,
it becomes pix/1   *   1/(pix/yr) and pix then cancels...
hard to show this way...
lets try:

pix       1
---   * --------
 1        pix
          ---
           yr

=


pix  *   yr
---     -----
 1       pix

=

years


i think that was better...
the answer to your question then becomes solving:

480000^16.7M / 3.63e14

now, thats the same as:
480000^3^255/3.63e14

which is 1.11e17^255/3.63e14
which is 1.11e17^5^51/3.63e14
   =1.(11*5)e(17*5)^51/3.63e14
which is 1.65e85^51/3.63e14
and i can tell you right now...
this is going to be a *lot* of years...

1.65e85^51 = 1.(65*51)e(85*51) = 1.3315e4335/3.63e14

which, best i can figure :), is....

(if you move the decimal of the divisor, it makes it
  much easier to calculate...)
1.3315e4335/0.363e15
1.(3315-363)e(4335-15)
=
***********************
*  1.2952e4320 years  *
***********************
that's a 4K document holding like 99% zeros :)




anyone see any math mistakes? ;)


> Just curious.
> molasses
ummmm that's an awfully big curious, 4300 decimal places of curious...
:O

--Hawke'