Re: if statement not working
On 22 Mar 2002, at 17:07, kbochert at ix.netcom.com wrote:
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> I was going to use '=3D=3D' but then '=3D=3D' and '=3D' seem backwards to
> me.
> There is great scope for artistry here-- how about (=3D) or 
lol !
> >> that acts like '=3D' except that it
> >> plows on ahead in the face of errors:
> >> s =3D~ t[2..4]
> >> -- s is padded to length 3 if necessary
>
> >Since you specified [2..3], why pad s some more? And with what?
> > Better to look at what t actually has, and deliver what is in
> > the envelope of [2..3] and no more. If [2..3] doesn't exist,
> > then return {}. If you asked to borrow a book that i don't have,
> > i won't pad out a empty box of non-existant book with some
> > random selection of book parts.
>
> If I ask you for a book and you are missing the last chapter, I
> might appeciate getting what you have.
Yes. I surely would not glue in enough pages from other books to make up
the length of the original book, heh.
> Your [2..3] confused me, so to make the sample clearer:
> sequence t =3D "abcd"
> sequence s =3D t[3..6]
> I can see 4 possible results:
> 1) ""
> 2) "cd"
> 3) "cd "
> 4) Fatal Error
>
> I like 2), i.e. do the best you can.
I agree. Nothing else makes sense in safe processing. It also take care of
the req for "inf" as predefined constant, because defining it like:
constant len len = 500000000000000
s = "123456789"
?s[5..len] -- "56789"
(you know what i mean)
Kat
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