Re: Sequence Slicing (Was RE: Tough ciphers?)
- Posted by euman at bellsouth.net Mar 14, 2002
- 430 views
Last try.....then Im going to bed.
sequence z
integer aout
integer lenx
integer j
aout = a + 1
lenx = length(x)
z = repeat(0, lenx - aout)
j = 0
for i = aout to lenx do
j += 1
z[j] = x[i]
end for
x = z
Euman
euman at bellsouth.net
