Re: Sequence Slicing (Was RE: Tough ciphers?)

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----- Original Message ----- 
From: "C. K. Lester" <cklester at yahoo.com>
> They are of the pattern
> 
>     x = x[a+1..length(x)]

sequence z

integer aout
aout = a + 1

integer lenx
lenx = length(x)

z = repeat(0, lenz - aout)

for i = aout to lenx do
     z[i] = x[i]
end for

x = z

-- or just leave it z instead of the extra copy if you want!

BTW, completly untested to work or for speed but I imagine this might be
faster.......

Euman

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