Re: Defining long constants - do-able but not exactly elegant
- Posted by Kat <gertie at PELL.NET> Mar 14, 2002
- 407 views
On 15 Mar 2002, at 3:24, tone.skoda at siol.net wrote: > > This works fast: > > buffer = append (buffer, gets (fn)) > > This very very slow: > > buffer [1] = append (buffer [1], gets (fn)) > > I guess interpreter creates a copy of buffer [1] every time it is used as > parameter in append(). I thought the whole point of using append() is that Rob optimised it to not make copies? Kat
