OpenEuphoria

Re: PtInRect return value always zero....

• Posted by euman at bellsouth.net Aug 22, 2001
• 386 views

> From: <euman at bellsouth.net>
> > Hello,
> >
> > I need help with this, it doesnt seem to work at all...
> >
> > </snip>
> >
> > c_proc(xGetCursorPos, {pt} )
> >
> > junk = c_func(xScreenToClient, {hwnd, pt})
> >
> > c_proc(xGetWindowRect, {cntrl_id, rect}
> >
> > junk = c_func(xPtInRect, {rect, pt})
> >
> > <snip\>
> >
> > First I retrieve the CursorPos and convert this to ClientCoords
> > next, I retrieve the WindowRect which sets (rect) the coords to
> > ctrl_id and test to see if the ClientCoord (pt) resides within
> > WindowRect (rect) with xPtInRect..
> >
> > Very Simple and should work according to MS.... ;-0
> >
> > hwnd and ctrl_id's handle, rect and pt address's are aquired already
> > and, are valid id's and address's
> >
> > I traced this out by peeking the pt and rect values and
> > according to the info I recieved and, the position of the Cursor
> > relative to the ctrl_id area junk @ xPtInRect should be nonzero
> > but, it always returns zero.
> >
> > Anyone faced this problem?
> >
> > It's really a trivial problem, I have a method that works for what I need
> > to accomplish at the moment so, no-one strain for an answer..
> >
> > Euman
> > euman at bellsouth.net
> >
> 
> I think I've worked this one out, finally.
> 
> I believe the problem is that the parameters being passed are wrong.
> According to the SDK docs, you need to pass the address of a RECT structure
> and a POINT structure. 
> Note, it is not the address of the POINT, but the
> actual POINT structure itself.

Your very observant, I thought about this for about 10 minutes
after I wrote the question and dropped it because I used Euphoria's
internal methods which prove to be really fast and do the job..

Thanks Derek, I really didnt think anyone would get this one.

> 
> So may this is more like what is required...
> 
>   atom x,y
>   x = peek4u(pt)
>   y = peek4u(pt+4)
>  junk = c_func(xPtInRect, {rect, x, y})
> 
> ------
> Derek