OpenEuphoria

Re: RFC: Breaking existing Euphoria functionality

• Posted by Andy Serpa <ac at onehorseshy.com> Feb 22, 2007
• 578 views

Michael J. Sabal wrote:
> 
> Has anybody written a statement like this:
> 
> result = ({'a','b','c'} = {'a','b','f'})
> 
> and expected result to look like this:
> 
> ? result
> {1,1,0}?
> 
> Is there any code in the archives or recent user contributions (say less than
> 3 years old) that takes advantage of this functionality?
> 
I don't know about the user contributions, but I use this very Euphorian
capability ALL THE TIME.  Changing it would break almost a very high percentage
of the Eu programs I've written over the years.  Doing this kind of thing easily
is one of the top reasons I use Euphoria at all.

Don't break code, just add a new operator (== or whatever).  I for one would
like to see a conditional operator for sequence operations...