Re: RFC: Breaking existing Euphoria functionality
Michael J. Sabal wrote:
> Has anybody written a statement like this:
> result = ({'a','b','c'} = {'a','b','f'})
> and expected result to look like this:
> ? result
> {1,1,0}?
Yes. But it was a long time ago and for something trivial.
> Is there any code in the archives or recent user contributions (say less than
> 3 years old) that takes advantage of this functionality?
My guess would be probably not. :)
If you change the existing behavior, will you still allow the prior behavior
through some function or other way?
|
Not Categorized, Please Help
|
|
