Re: RNG Test: Code to generate Diehard file in Euphoria
- Posted by Brian Broker <bkb at CNW.COM> Feb 17, 2000
- 726 views
Earlier I wrote (in response to Rett): >random_atom = rand( #FFFF ) > >I will get a result between #00000001 and #0000FFFF which is clearly a 16- >bit random number that excludes the possibility of getting a result of >#0000. I also meant to say that because of the above reasoning, the program you wrote would not meet the input criteria for DieHard... -- Brian
