Re: Faster lower() command
- Posted by Jesse Adkins <Tassadar29 at lycos.com> Jan 20, 2007
- 536 views
To clarify for everyone, this is what I used for benchmarking.
constant ITERATIONS = 1000000 integer p atom t0, loop_overhead t0 = time() for i = 1 to ITERATIONS do -- time an empty loop end for loop_overhead = time() - t0 t0 = time() for i = 1 to ITERATIONS do p = power(2, 20) end for ? (time() - t0 - loop_overhead)/ITERATIONS -- calculates time (in seconds) for one call to power
It's the code directly from the documentation under the time() command. I swapped out 'p = power(2, 20)' for my own command. Quoting the mail I sent to Rob Craig... Converting the sequence ("A REALLY LONG SEQUENCE WITH JUNK INSIDE.") Old -> (2.26 to 2.28 e-06) New -> (1.34 to 1.36 e-06) The benchmarks were done on Windows XP Home. -- Jesse Adkins