OpenEuphoria

Re: memory

• Posted by Kat <gertie at PELL.NET> Jul 12, 2001
• 421 views

On 12 Jul 2001, at 19:04, martin.stachon at worldonline.cz wrote:


> 
> Kat writes :
> > Hey all,,
> >
> > I have a short program that opens a 6.8megabyte file, containing text
> > separated by lots of {0}. The object is to eliminate the {zero}s, and
> reformat
> > the results to a more text-looking file. What i can't figure is that
> Taskinfo
> > says Eu is using 86Megabytes in memory to do it!
> >
> > Are these the lines doing it? Is a new instance of data created every time
> it
> > is mentioned in the line?:
> >
> > puts(1,"removing 10 nulls\n")
> > place = match({0,0,0,0,0,0,0,0,0,0},data)
> > while place do
> >  data = data[1..place] & data[place+10..length(data)]
> >  place = match({0,0,0,0,0,0,0,0,0,0},data)
> > end while
> >
> >
> > Kat
> >
> 
> Hello Kat,
> 
> Wouldn't be a better way to do the job this code?:
> 
> include file.e
> include get.e
> integer fn
> fn = open("file.txt","rb")
> integer char
> sequence result
> result = {}
> while 1 do
>     char = getc(fn)
>     if char = -1 then exit -- EOF
>     eslif char = 0  then -- ignore
>     else result &= char -- append to the result
>     end if
> end while
> close(fn)

That way makes 6.8 million file accesses. Eventually, i went to pruning a 
little off the front of data in a loop, and processing 50 bytes at a time. The 
program eventually was using 120megs of ram and was thrashing the 
harddrive for 6 hours, so i killed it off.

I'd still like to know why it wanted so much memory for a little 6.8meg text 
file.

Kat