allocate_string() question

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When using allocate_string() as a paramter, is it freed automatically =
after the routine is called? So

atom str
str =3D allocate_string("string")
call_something(str)
free(str)

is same as :

call_something(allocate_string("string"))
-- automatically freed ?


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<DIV><FONT face=3D"Arial CE" size=3D2>When using allocate_string() as a =
paramter, is=20
it freed automatically after the routine is called? So</FONT></DIV>
<DIV>&nbsp;</DIV>
<DIV><FONT face=3D"Arial CE" size=3D2>atom str</FONT></DIV>
<DIV><FONT face=3D"Arial CE" size=3D2>str =3D =
allocate_string("string")</FONT></DIV>
<DIV><FONT face=3D"Arial CE" size=3D2>call_something(str)</FONT></DIV>
<DIV><FONT face=3D"Arial CE" size=3D2>free(str)</FONT></DIV>
<DIV>&nbsp;</DIV>
<DIV><FONT face=3D"Arial CE" size=3D2>is same as :</FONT></DIV>
<DIV>&nbsp;</DIV>
<DIV><FONT face=3D"Arial CE"=20
size=3D2>call_something(allocate_string("string"))</FONT></DIV>
<DIV><FONT face=3D"Arial CE" size=3D2>-- automatically freed =
?</FONT></DIV>
<DIV>&nbsp;</DIV>
<DIV><FONT face=3D"Arial CE"=20

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