Last Element Notation
- Posted by Derek Parnell <ddparnell at bigpond.com> Sep 17, 2003
- 546 views
Robert, AAARRRGRGGRRGGR!!!! Please, please, reconsider some syntax notational assistance for accessing the last element in a sequence! The current piece I'm working on often needs to reference the last element of a sequence, and often that is a deeply nested sequence. This causes the program code to become VERY VERY *&%$ at &!* at ^ unreadable. Sure, I can write some neat routines that do this but I'm trying to avoid the overhead (however bloody slight) of a routine call. So that this ... FB_Content[lBuffer][lLine] = FB_Content[lBuffer][lLine][1..lCol-1] & pText & FB_Content[lBuffer][lLine][lCol..length(FB_Content[lBuffer][lLine])] can become something like ... FB_Content[lBuffer][lLine] = FB_Content[lBuffer][lLine][1..lCol-1] & pText & FB_Content[lBuffer][lLine][lCol..$] or even better, a couple of built-in routines... FB_Content[lBuffer][lLine] = insert(FB_Content[lBuffer][lLine], lCol, pText) and to simplify the extremely common idiom of removing the last element... if equal(pText[i][$], '\n') then pText[i] = remove_right(pText[i], 1) end if instead of the hard-to-read ... if equal(pText[i][length(pText[i])], '\n') then pText[i] = pText[i][1..length(pText[i])-1] end if Its little things like this that make Euphoria so frustrating, when the solution, from the point of view of your customers, is so simple. Please help us. -- cheers, Derek Parnell