Bits and Bytes: New Ranch flavour!
------=_NextPart_000_007E_01C01199.7F702BA0
charset="iso-8859-1"
Content-Transfer-Encoding: quoted-printable
In responce to my question about the black box around bitmaps, David =
Cuny wrote:
Converts the bitmap into 'slices', and remove the 'invisible' color. For
example, consider the box in this bitmap. The outer border is color 1, =
the
inner border is color 2, and the inner color is color 0 (invisible).
111111
122221
120021
120021
122221
111111
This can be broken into the following:
{ 0, 0, {1,1,1,1,1,1} }
{ 0, 1, {1,2,2,2,2,1} }
{ 0, 2, {1,2} }
{ 4, 2, {2,1} }
{ 0, 3, {1,2} }
{ 4, 3, {2,1} }
{ 0, 4, {1,2,2,2,2,1} }
{ 0, 5, {1,1,1,1,1,1} }
The first two values indicate where to place the scanline, relative to =
the
origin. The sequence following represents the pixels to draw.
-- David Cuny
But, how do I do that? It's a little too complicated, I don't know much =
about bits and bytes. Can someone help simplify?
Thnks
Thomas
------=_NextPart_000_007E_01C01199.7F702BA0
charset="iso-8859-1"
Content-Transfer-Encoding: quoted-printable
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
<HTML><HEAD>
<META content=3D"text/html; charset=3Diso-8859-1" =
http-equiv=3DContent-Type>
<META content=3D"MSHTML 5.00.2614.3500" name=3DGENERATOR>
<STYLE></STYLE>
</HEAD>
<BODY bgColor=3D#ffffff>
<DIV><FONT face=3DArial size=3D2>In responce to my question about the =
black box=20
around bitmaps, David Cuny wrote:</FONT></DIV>
<DIV> </DIV>
<DIV><FONT face=3DArial size=3D2>Converts the bitmap into 'slices', and =
remove the=20
'invisible' color. For<BR>example, consider the box in this bitmap. The =
outer=20
border is color 1, the<BR>inner border is color 2, and the inner color =
is color=20
0=20
111<BR><BR>This=20
can be broken into the following:<BR><BR> { 0, 0, =
{1,1,1,1,1,1}=20
}<BR> { 0, 1, {1,2,2,2,2,1} }<BR> { 0, 2, {1,2}=20
}<BR> { 4, 2, {2,1} }<BR> { 0, 3, {1,2}=20
}<BR> { 4, 3, {2,1} }<BR> { 0, 4, {1,2,2,2,2,1}=20
}<BR> { 0, 5, {1,1,1,1,1,1} }<BR><BR>The first two values =
indicate=20
where to place the scanline, relative to the<BR>origin. The sequence =
following=20
represents the pixels to draw.<BR><BR>-- David Cuny</FONT></DIV>
<DIV> </DIV>
<DIV><FONT face=3DArial size=3D2>But, how do I do that? It's a little =
too=20
complicated, I don't know much about bits and bytes. Can someone help=20
simplify?</FONT></DIV>
<DIV> </DIV>
<DIV><FONT face=3DArial size=3D2>Thnks</FONT></DIV>
<DIV> </DIV>
------=_NextPart_000_007E_01C01199.7F702BA0--
|
Not Categorized, Please Help
|
|