OpenEuphoria

Re: Example where Euphoria defaults on a boolean expression

• Posted by Juergen Luethje <jluethje at gmx.de> Nov 23, 2002
• 653 views

Rom wrote:

<snip>

> "not E and E" is unsolvable, neither true nor false.

No. "not E and E" is always false, of course.

> Euphoria cannot handle this (like C and Pascal).

No, please try:

integer E
E = 0
? not E and E
E = not E
? not E and E


Regards,
   Juergen